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ludmilkaskok [199]
2 years ago
8

In a regular 52 deck of cards, what is the probability of picking a random spade, a 4 of any suit and then a random diamond with

replacement?
Mathematics
1 answer:
meriva2 years ago
5 0

sample \: space = 52 \: cards \\ spades = 13 \: cards \\ number \: 4s = 4 \: cards \\ diamonds = 13 \: cards \\ note \: that =  \\ there \: is \: replacement \\ order \: does \: matter

P( \gamma ) =  \frac{13}{52}  \times  \frac{4}{52}  \times  \frac{13}{52}  =  \frac{1}{208}

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Ne4ueva [31]

Answer:

Taking into account the values showed for this food (image attached). It is required

5  

Servings.  

Step-by-step explanation:

The total calcium (Cat) required is 1300 mg/day.  

One serving of this food can have 260 mg.  

First step is to suppose one day of calculation. t = 1 day.

Cat = (1300 mg/day)(1 day) = 1300 mg Calcium.

One single serving can have 260 mg Calcium (Cas). So, we need to calculate the amount of servings (N) required to complete 1300 mg.

Cat = Cas*N

N = Cat/Cas = 1300 mg/260mg

N = 5.

Finally amount of servings is five N = 5.  

8 0
3 years ago
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Answer:

4(5x + 6)

Step-by-step explanation:

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5 0
4 years ago
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Step-by-step explanation:

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