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ludmilkaskok [199]
2 years ago
8

In a regular 52 deck of cards, what is the probability of picking a random spade, a 4 of any suit and then a random diamond with

replacement?
Mathematics
1 answer:
meriva2 years ago
5 0

sample \: space = 52 \: cards \\ spades = 13 \: cards \\ number \: 4s = 4 \: cards \\ diamonds = 13 \: cards \\ note \: that =  \\ there \: is \: replacement \\ order \: does \: matter

P( \gamma ) =  \frac{13}{52}  \times  \frac{4}{52}  \times  \frac{13}{52}  =  \frac{1}{208}

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7 0
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Answer:

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Step-by-step explanation:

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3 years ago
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Delicious77 [7]

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Step-by-step explanation:

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          I personally ignore the picture and use the labels of "triangle RST and triangle XYZ" that the problem gives <em>because</em> the XYZ picture is not lined up with the similarity it has with RST.

(A) says that side ST is corresponding with side YZ,

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          -> Correct

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4 0
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