How much sodium acetate is needed to make acetic acid neutral?

Chemistry

1 answer:

Zigmanuir [339]3 years ago

4 0

2.5 mL sodium acetate is needed to make 250 mL of the acetic acid.

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During a titration, the pH of an analyte solution containing HA(aq) is 3.92 and the ratio of [A–]/[HA] is 0.41. What is the Ka o

Solnce55 [7]

Answer:

$Ka=4.71x10^{-4}$

Explanation:

Hello there!

In this case, according to the Henderson-Hasselbach equation, it is possible to write:

$pH=pKa+log(\frac{[A^-]}{[HA]} )$

Next, since we are given the pH and the [A–]/[HA] ratio, we can solve for the pKa as shown below:

$pKa=pH-log(\frac{[A^-]}{[HA]} )$

Now, we plug in the values to obtain:

$pKa=3.92-log(0.41 )\\\\pKa=3.33$

Next, Ka is:

$Ka=10^{-pKa}=10^{-3.33}\\\\Ka=4.71x10^{-4}$

Best regards!

3 0

3 years ago

Give an example of a solution that can be seperated by simple distilation.

Juliette [100K]

Answer: Evaporation of salt water

Explanation: During the process of evaporating salt water which involves simple distillation, pure water is separated with salt molecules.

When heated water evaporates from the solution since it is less dense. When condensed it becomes pure water and salt is left out since it is more denser.

8 0

3 years ago

After 15 minutes, 30 g of a sample of polonium-218 remain unchanged. If the original sample had a mass of 960 g, what is the hal

Keith_Richards [23]

Q1. The answer is 3 minutes.

Let's first calculate the remaining amount in percent:
If 960g is 100 percent (starting amount), 30 g is how many percents:
960 g : 100% = 30 g : x
x = 30 g * 100% / 960 g = 3.125% = 0.03125

Now, using the formula to calculate the number of half-lives:
(1/2)ⁿ = x,
where
x is the remaining amount: x = 0.03125
n is the number of half-lives
1/2 stands for half-life.

(1/2)ⁿ = 0.03125
⇒ n*log(1/2) = log(0.03125)
n = log(0.03125)/log(1/2) = log(0.03125)/log(0.5) = -1.505/-0.301 ≈ 5

The number of half-lives is 5.
Now, <span>the number of half-lives (n) is a quotient of total time elapsed (T) and length of half-life (L):
n = T/L
We know:
n = 5
T = 15 min
L = ?

Thus
L = T/n
L = 15 min/5 = 3 minutes

Q2. Filtration should be chosen.
Filtration and distillation are used to separate mixtures - filtration for the separation of heterogeneous mixtures and </span>distillation for the separation of homogeneous mixtures. Imagine that your pile of soil is a mixture. It consists of different components (the leaves, acorns, twigs), so it is the heterogeneous mixture. Therefore, to separate the leaves, acorns, twigs you will use filtration.

5 0

4 years ago

as a gas occupied a volume of 250cc at 250at 700mm pressure temperature,25degree Celsius what additional pressure is required?re

Allisa [31]

Additional pressure required : 175 mm

<h3>Further explanation</h3>

Boyle's Law

At a constant temperature, the gas volume is inversely proportional to the pressure applied

$\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$