<span>Answer: The 1 kg of water will reach the lowest temperature
</span>
Both of the objects is water so their specific heat should be same. The heat removed from the 2kg of water which is 2 times of mass than the 1kg water. Since the heat removed, both of their temperatures will drops. But 2kg water temperature drops will be half of 1kg water.
Explanation:
For the given equation:
NH3 + HCl -> NH4Cl
This is an acid-base reaction (neutralization): NH3 is a base, HCl is an acid and NH4Cl is the sal.
Answer: b) NH3 is the base and NH4CI is the salt.
Approx.
15
⋅
g
of metal.
Explanation:
Moles of iron oxide,
F
e
2
O
3
=
21.6
⋅
g
159.69
⋅
g
⋅
m
o
l
=
0.135
⋅
m
o
l
with respect to the oxide.
But by the composition of the oxide, there are thus
2
×
0.135
⋅
m
o
l
×
55.8
⋅
g
⋅
m
o
l
−
1
iron metal
=
?
?
g
.
An extraordinary percentage of our budgets goes into rust prevention;
iron(III) oxide
is only part of the redox chemistry. Once you put up a bridge or a skyscraper, which is inevitably steel-based structure, it will begin to corrode.
Answer:
0.46M NaS₂O₃ (Assuming KIO₃ solution with a concentration of 1.0M)
Explanation:
Based on the reaction:
6 Na₂S₂O₃ + KIO₃ + 5 KI + 3 H₂SO₄ → 3 Na₂S₄O₆ + 3 H₂O + 3 K₂SO₄ + 6 NaI
<em>6 moles of Na₂S₂O₃ react per mole of KIO₃</em>
Assuming the molarity of the KIO₃ solution is 0,1M:
Moles of KIO₃: = 5.0x10⁻³L ₓ (0.1 mol / L) = <em>5.0x10⁻⁴ moles</em>
As 6 moles of thiosulfate reacted per mole of iodate:
5.0x10⁻⁴ moles KIO₃ ₓ (6 moles Na₂S₂O₃ / 1 mole KIO₃) =
<em>3.0x10⁻³ moles of Na₂S₂O₃. </em>In 6.5mL (6.5x10⁻³L):
3.0x10⁻³moles Na₂S₂O₃ / 6.5x10⁻³ L = 0.46M NaS₂O₃
Answer:
363.64g of oxygen would be required.
Explanation:
1) Write and balance the combustion equation for propane.
Propane + Oxygen --> carbon dioxide + water
C3H8 + O2 --> CO2 + H2O
Upon balancing, we have;
C3H8 + 5O2 --> 3CO2 + 4H2O
2) How many grams of oxygen are required to burn 200 grams of propane.
From the reaction;
Propane = (3 * 12) + (8 * 1) = 44
Oxygen = (5 * 16) = 80
80 grams of oxygen is required to combust 44g of propane.
80 = 44
x = 200
x = ( 80 * 200 ) / 44
x = 363.64g
