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3 years ago

10

Tina and three of her friends are in line with different amounts of money. The first person in line had $775. If the amount trip

led for each of Tina's friends, how much would they have altogether?

1 answer:

nataly862011 [7]3 years ago

4 0

37,975 dollars altogher

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To solve a problem, we often _________ the given information into algebraic expressions and equations.

bulgar [2K]

$\frac{-b\pm\sqrt{b^2-4ac}}{4a}$

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3 years ago

In one month you earned $100 delivering newspapers if you deposit the money in a savings account with a simple interest rate of

saw5 [17]

In 6 months, Simple interest of $6 will be earned for investing $100.

<u>Step-by-step explanation:</u>

Step 1:

Given details are Principal (P) = $100, SI rate (R) = 12%, Time (T) = 6 months = 0.5 years

Step 2:

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2 years ago

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3 years ago

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

6 0

1 year ago

Find the output, y, when the input, x , is 7.<br> y=

Anton [14]

The answer to your question would be 6!

4 0

2 years ago