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3 years ago

10

Tina and three of her friends are in line with different amounts of money. The first person in line had $775. If the amount trip

led for each of Tina's friends, how much would they have altogether?

1 answer:

nataly862011 [7]3 years ago

4 0

37,975 dollars altogher

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Which term of the AP . 27, 24, 21, .... is zero?

dmitriy555 [2]

Answer: 27,24,21....

d=24-27=-3 a=27

let nth term=0

a+(n-1)d=0

27+(n-1)-3=0

(n-1)-3=-27

n-1=9

n=10

Step-by-step explanation:

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3 years ago

Help asapppp porfas

iren2701 [21]

<h3>Answer: triangular prism </h3>

Step-by-step explanation:

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3 years ago

Geo: Worth 50 points and I will give brainliest to right answer! #24

Sindrei [870]

1. ∠1 ≅ ∠3 1. given

∠1 and ∠6 are supplementary angles

∠3, ∠4, and ∠5 are supplementary angles

2. m∠1 = m∠3 2. definition of congruency

3. m∠1 + m∠6 = 180° 3. definition of supplementary angles

m∠3 + m∠4 + m∠5 = 180°

4. m∠3 + m∠4 + m∠5 = m∠1 + m∠6 4. transitive property

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2 years ago

Humood's house is (-5,7)

grin007 [14]

The distance from Humood's house to the school is 500m

<h3>How to determine the distance from Humood's house to the school?</h3>

The given parameters are:

Humood's house is (-5,7)

The school is (3,1)

The distance between both points is calculated using

$d = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2$

Substitute the known values in the above equation

$d = \sqrt{(-5 - 3)^2 + (7 - 1)^2$

Evaluate

d = 10

Each unit in the graph is 50m.

So, we have

Distance =10 * 50m

Evaluate the product

Distance = 500m

Hence, the distance from Humood's house to the school is 500m

Read more about distance at

brainly.com/question/1872885

#SPJ1

8 0

1 year ago

For better clarification I guess

marissa [1.9K]

Answer:

1.) $=\frac{\sqrt{3}}{3}$

2.) $42\sqrt{30}$

Step-by-step explanation:

1.) $\mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{3}}{\sqrt{3}}$

2.) $\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{b}=\sqrt{a\cdot b}$

$\sqrt{6}\sqrt{5}=\sqrt{6\cdot \:5}$

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2 years ago