Answer:
The actual tower would be 45 ft wide.
Step-by-step explanation:
In order to find the width, we need to determine the scale factor. We can do that by dividing the actual height by the model height.
60ft:24in = 15ft:6in = 2.5ft:1in
Now we use that scale factor to determine the width. Multiply the scale factor by the width of the model.
18 inches * 2.5ft/in = 45 feet
(1,52)(-1,-52) (2,26)(-2,-26)(4,13)(-4,-13)(1/2,104), etc etc etc
Answer:

Step-by-step explanation:
Hello,
a and b are the zeros, we can say that

So we can say that

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write

and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes

multiply by 3

Answer:
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Step-by-step explanation:
Here n= 20
Sample mean GPA = x`= 2.84
Standard mean GPA = u= 2.55
Standard deviation = s= 0.45.
Level of Significance.= ∝ = 0.01
The hypothesis are formulated as
H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students
against the claim
Ha: u1≠u2
i.e the GPA of night students is different from the mea GPA of day students
For two tailed test the critical value is z ≥ z∝/2= ± 2.58
The test statistic
Z= x`-u/s/√n
z= 2.84-2.55/0.45/√20
z= 0.1441
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Answer:
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