All categories

3 years ago

Katy used 3/4 of a 6 ft board for a science fair project. How many inches did she use?

1 answer:

5 0

She used 54 inches. 3/4 is equal to .75 so you can find 3/4 of the board by taking the fool length and multiplying it by .75 so 6•.75=4.5. So 3/4 of the board is 4.5 ft. However, the answer has to be in inches so since there are 12 inches in a foot you multiply 4.5•12 and that gives you your answer:54 inches.

You might be interested in

Nine pieces of 8 in. ✕ 12 in. duct that is 2 2 3 ft in length is needed for a building. What is the total length (in ft) needed?

kodGreya [7K]

This question is incomplete, the complete question is;

Nine pieces of 8-in. × 12-in. duct that is 2 $\frac{2}{3}$ ft in length is needed for a building. What is the total length (in ft) needed?

Answer:

the total length needed is 24 ft

Step-by-step explanation:

Given the data in the question;

the length of one piece of 8-in. × 12-in. duct is 2 $\frac{2}{3}$ ft

Now to find the total length for nine pieces of the duct;

we simple multiply 2 $\frac{2}{3}$ ft by nine

Total length = 9 × 2 $\frac{2}{3}$

we convert the mixed fraction to improper fraction

2 $\frac{2}{3}$ = 8/3

Total length = 9 × (8/3) ft

Total length = 24 ft

Therefore, the total length needed is 24 ft

8 0

3 years ago

Semielliptical Arch Bridge An arch for a bridge over a highway is in the form of half an ellipse. The top of the arch is 20 feet

photoshop1234 [79]

Answer:

the span of the bridge is 73.7 feet

Step-by-step explanation:

The equation of an ellipse with a vertical major axis(i.e major axis parallel to y axis) is given by:

$\frac{(x-h)^{2} }{b^{2} } + \frac{(y-k)^{2} }{a^{2} }= 1$ a>b

where (h,k) are the coordinates of the center of the ellipse, a is the length of the major axis and b is the length of the minor axis

For this problem, the center of the ellipse (h,k) = (0,0)

Therefore:

$\frac{(x)^{2} }{b^{2} } + \frac{(y)^{2} }{a^{2} }= 1$

The top of the arch is 20 feet above the ground level (the major axis), therefore a=20

length of the major axis = 2a= 2*20 = 40

$\frac{x^{2} }{b^{2} } + \frac{y^{2} }{20^{2} }= 1\\\frac{x^{2} }{b^{2} } + \frac{y^{2} }{400 }= 1$

The coordinates of the ellipse (x,y) = (28,13)

$\frac{28^{2} }{b^{2} } + \frac{13^{2} }{400 }= 1$

$\frac{28^{2} }{b^{2} } + 0.4225= 1$

$\frac{784 }{b^{2} } = 0.5775$

b² ≅ 1358

b≅36.85

Length of minor axis (2b) = 73.7 feet.

the span of the bridge is 73.7 feet

7 0

3 years ago

Yuri purchased 8 trees to have planted at his house. The store charged a delivery fee of $5 per tree.The total cost of the trees

garri49 [273]

$168 - (8 times $5)=
$168 - $40 =
$128 = 8 trees
1 tree = $128 divided by 8=
1 tree = $16

8 0

2 years ago

Find the measure of ∠BAC. Create another angle with the same measure. Measure the new angle to verify that it has the same angle

Strike441 [17]

Answer:

The position and orientation of the new angle may vary, but it should have the same angle measure as ∠BAC

.Step-by-step explanation:

4 0

2 years ago

HELP MATH

aleksley [76]

Answer:

18.84 is the answer

Step-by-step explanation:

Can I please be marked as brainlist

8 0

3 years ago