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MrRissso [65]
3 years ago
15

Plz help me im begging u to help

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
8 0

Answer:

356 miles a day nkw help me

nika2105 [10]3 years ago
3 0

Answer:

356 miles

Step-by-step explanation:

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Musya8 [376]
The answer you already have selected in the image is correct. Even eyeballing it, you can see that the smaller shape fits into the larger shape 4 times.
4 0
2 years ago
Which fraction has the value that's equal to 3/4
mamaluj [8]

One of the fractions that’s equal to \frac{3}{4} is \frac{12}{16}

<u>Solution:</u>

Given that , we have to find fractions which has the same value as that of the fraction \frac{3}{4}

Now, we know that, there are several fractions with values equal to \frac{3}{4}

To find them, just multiply the numerator and denominator by the same number.

\begin{array}{l}{3 \times 2=6} \\\\ {4 \times 2=8}\end{array}

Therefore, \frac{6}{8} is equal to \frac{3}{4}

We can do the same with 4, to get \frac{12}{16}, or any other number beyond that.

Hence, one of the fractions that’s equal to \frac{3}{4} is \frac{12}{16}

4 0
3 years ago
Need some help with this question please.
Ksivusya [100]
Use Pythagorean theorem
a^2 + b^2 = c^2
Plug in the info
b = 53, a = 41
41^2 + 53^2 = c^2
1681 + 2809 = c^2
c^2 = 4490
Squareroot of 4490 = 67.007
Perimeter = adding all sides
53m + 41m + 67.01m = 161.01 m

Solution: 161.01 meters
8 0
2 years ago
I needdd helpppp I’ll give u brainlest
IgorC [24]

Answer:

1

Step-by-step explanation:

8 0
2 years ago
a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

3 0
3 years ago
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