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Alik [6]
3 years ago
8

Write an equation in point-slope form of the line that passes through the given point and with the given slope, m

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0
Equation format for a slope, m and a point (x1, y1)

y - y1  = m(x - x1)      (Try and memorize this formula)

8) for (3,-4),  m = 6.    x1 = 3,  y1 = -4, Substituting
y - y1  = m(x - x1)
y - (-4)  = 6(x - 3)
y + 4  = 6x - 18
y = 6x - 18 - 4
y = 6x - 22

10) for (-2,-7),  m = 4/5.    x1 = -2,  y1 = -7, Substituting
y - y1  = m(x - x1)
y - (-7)  = (4/5)*(x - (-2))
y + 7  = (4/5) *(x +2)                      4/5 = 0.8
y + 7  = 0.8x  + 1.6
y = 0.8x + 1.6-7
y = 0.8x - 6.4
y = (4/5)x - (64/10)
y = (4/5)x - (32/5)

So same approach to solve others. Cheers.
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Find the equation of a line that passes through the point (2,-5) and is perpendicular to the y-axis. Do not put any spaces in yo
Allushta [10]

Answer:

<em>y=-5</em>

Step-by-step explanation:

<u>Equation of the line</u>

Lines can be expressed in several forms. The slope-intercept form of the line is:

y = mx + b

Where m is the slope of the line and m is the y-intercept.

If the line is perpendicular to the y-axis, then it's a horizontal line. Horizontal lines have slope m=0, thus, the equation is:

y = b

To find the value of b, just substitute the given point:

-5=b

The equation of the line is:

y=-5

3 0
2 years ago
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gavmur [86]
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5 0
2 years ago
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QUESTION 9 of 10: You bought 100 shares of stock at $15 per share. You sold your 100 shares at $21.75 per share. Calculate your
Zarrin [17]

Answer:

Step-by-step explanation:

Multiply 100*$15 to find the loss. (1500)

Multiply 100*$21.75 to find what was made. (2175)

Subtract 2175-1500

Total=$675

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2 years ago
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Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
2 years ago
A farmer has 100 m of fencing to enclose a rectangular pen. Which quadratic equation gives the area (A) of the pen, given its wi
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A(w)=50w-w2 if the perimeter is 100, I plugged in possible values for the width...I used w=15 and length = 35 for a perimeter of 100. then I plugged these values in the possible equations until I found the correct one giving me an area of 525 (15x35) . I could not think of an easier way.

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3 years ago
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