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Alik [6]
3 years ago
8

Write an equation in point-slope form of the line that passes through the given point and with the given slope, m

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0
Equation format for a slope, m and a point (x1, y1)

y - y1  = m(x - x1)      (Try and memorize this formula)

8) for (3,-4),  m = 6.    x1 = 3,  y1 = -4, Substituting
y - y1  = m(x - x1)
y - (-4)  = 6(x - 3)
y + 4  = 6x - 18
y = 6x - 18 - 4
y = 6x - 22

10) for (-2,-7),  m = 4/5.    x1 = -2,  y1 = -7, Substituting
y - y1  = m(x - x1)
y - (-7)  = (4/5)*(x - (-2))
y + 7  = (4/5) *(x +2)                      4/5 = 0.8
y + 7  = 0.8x  + 1.6
y = 0.8x + 1.6-7
y = 0.8x - 6.4
y = (4/5)x - (64/10)
y = (4/5)x - (32/5)

So same approach to solve others. Cheers.
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See explanations

Step-by-step explanation:

1.

Choosing the product of power property,when you multiply exponentials with the same base , you add their exponents.

This is represented as :

(x^a)*(x^b)=(x^{a+b)}

This property is true in that ;

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3 0
3 years ago
"What is the input value for which f (x) = 3?" <br><br> Please Help!!!!! URGENT!!!
Stella [2.4K]

Answer:

x=-3

Step-by-step explanation:

Since f(x) also means y, we are looking for a point where y=3

When x=-3, we see that y reaches 3

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5 0
2 years ago
Read 2 more answers
The equation y 16t 2 18t 405 describes the height in feet of a ball thrown downward at 18 feet per second from a height of 405 f
kumpel [21]

Answer:

Ball hits the ground after 4.5 sec

Step-by-step explanation:

Let a -1, so that the leading coefficient is positive

So our quadratic is

-1 \times (16t^2 +18t -405)

The key coefficients of two binomial variables can be 1 and 16, or 2 and 8, or 4 and 4, for the leading coefficient of 16.

Yet they can't actually be 4 and 4 because the linear (x) term coefficient has to be a multiple of 4, which it isn't and leading coefficients 1 and 16 on the binomial factors is not likely.

So, 2 and 8 taken as the leading coefficients of  two binomial factors.

For constant  405, possible factorizations are (81\times 5, 27 \times 15, 9 \times 45).

(16t^2 +18t -405) = (8t + 45) (2t - 9)

Taking first factor, thus we find  negative value for given time t. But  second time equivalent to zero gives the value of 4.5 for t

Thus ball hits the ground after 4.5 sec

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3 years ago
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liberstina [14]
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8 0
3 years ago
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Olegator [25]
(4, 3) i think lol goodluck
6 0
3 years ago
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