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Serjik [45]
2 years ago
5

10. Write and solve an equation that means “a number (n) divided by 4, plus 3 is 7."

Mathematics
2 answers:
Artist 52 [7]2 years ago
8 0

N=16

not how to write the equation

olya-2409 [2.1K]2 years ago
3 0
Pretty sure this would be correct

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WHAT IS 1/2 + 3/4 PLZ ANSWER REALLY REALLY URGENT!!!!!!!!!!!!!
Gnesinka [82]

Answer:   it is 1.25

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Last summer we took an auto trip of 3427 miles . After we had driven 1578 miles , how many are left ?
koban [17]
There wold be 1,849miles left.
7 0
3 years ago
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I NEED HELP
noname [10]

Answer:

You can use a number line to subtract -6 from -7. The difference is -1.

6 0
2 years ago
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50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

(DE)^2+(DF)^2=(EF)^2

Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

6 0
3 years ago
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How do i write a two column proof for this??<br><br>Given: PG ≅ SG and PT ≅ ST . Prove: ∠GPT ≅ ∠GST
Nikolay [14]

Answer:

PG ≅ SG (Given)

PT ≅ ST (Given)

GT = GT (Common)

∴ ∠GPT ≅ ∠GST (SSS Congruency Axiom)

Step-by-step explanation:

<u>Given</u>: PG ≅ SG and PT ≅ ST

<u>To Prove</u>: ∠GPT ≅ ∠GST

<u>Proof</u>:  PG ≅ SG (Given)

PT ≅ ST (Given)

GT = GT (Common)

∴ ∠GPT ≅ ∠GST (SSS Congruency Axiom).

<u>SSS Congruency Axiom</u>:  If three pairs of sides of two triangles are equal in length, then the triangles are congruent.

<u>Congruence</u>: Two sets of points are called congruent if, and only if, one can be transformed into the other by an isometry, i.e., a combination of rigid motions, namely a translation, a rotation, and a reflection. This means that either object can be repositioned and reflected (but not resized) so as to coincide precisely with the other object. Two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure.

7 0
3 years ago
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