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Keith_Richards [23]
3 years ago
13

Write the equation for a circle that satisfies the given conditions.

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

The standard form of a circle is:

(x-a)^2+(y-b)^2=r^2

Your center is (-10,  -6) and your radius is 9

Plug them into the equation and you get

(x-(-10))+(y-(-6)) = 9^2

(x+10)^2 + (y+6)^2=81

The correct answer is D.

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Bezzdna [24]

Answer:

21 19/25

Step-by-step explanation:

21 76/100

divide 76 and 100 by 4

21 19/25

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Toko follows a budget to buy supplies to paint his room. He spends 1/2 of his budget on a roller, a tray, and tape. He spends $1
Natasha_Volkova [10]
The answer is $36.

B - budget
So the calculation is as following:
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B= \frac{1}{2} B + 18
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3 0
3 years ago
Find the inertia tensor for an equilateral triangle in the xy plane.
ivanzaharov [21]
Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
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Can anyone help me solve this.I need proper equation..Thanks​
artcher [175]

Answer:

y = 9\sqrt{2}

Step-by-step explanation:

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sin45° = \frac{1}{\sqrt{2} }

sin45° = \frac{opposite}{hypotenuse} = \frac{9}{y}

Multiply both sides by y

y × sin45° = 9, that is

y × \frac{1}{\sqrt{2} } = 9

Multiply both sides by \sqrt{2}

y = 9\sqrt{2}

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