Question

Write the equation for a circle that satisfies the given conditions.

Answer 1

The standard form of a circle is:

$(x-a)^2+(y-b)^2=r^2$

Your center is $(-10, -6)$ and your radius is $9$

Plug them into the equation and you get

$(x-(-10))+(y-(-6)) = 9^2$

$(x+10)^2 + (y+6)^2=81$

The correct answer is D.