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Over [174]
3 years ago
11

I can’t find answers to this question. Please help.

Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Answer:

Did you try looking it up

Step-by-step explanation:

sorry If I am wrong and don't forget to make me brainliest

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Answer asap
Lana71 [14]
Two figure in front

h=16+17 = 33 m
l=18 m
width = 13 m
Volume = lwh = 18*13*33 =7722 m^2

Two figures at the back

h=16 m
l=18+18 =36 m
width = 15 m

Volume = lwh =36*15*16 =8640 m^2

Total volume = 7722+8640 = 16362 m^2
5 0
3 years ago
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval?
timama [110]
The Mean Value Theorem:
If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that:
f ` ( c )=  ( f ( b ) - f ( a ) ) / ( b - a )
f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 )
f `( x ) = 10 x - 3
f ` ( c ) = 10 c - 3 
2 f ` ( c ) = 16 - 2
f ` ( c ) = 7
7 = 10 c - 3
c = 1
Answer:
          Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).
4 0
3 years ago
The product of 5 and a number x is greater than 20<br> an inequality is ?<br> the solution is?
igor_vitrenko [27]

Answer:5*x>20

Step-by-step explanation: i think it is askinng to find x by comparing grater than less than

7 0
3 years ago
Steven starts a savings account with $10,000. He earns 7% annual interest. How much will be in the account after 6 years. Round
sveta [45]

So the equation is A = P(1+rt)
A = 10,000(1+0.07*6)
A = 10,000(1+0.42)
A = 14,200.00

7 0
3 years ago
The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15
katrin [286]
<h2>Hello!</h2>

The answer is: The first graphic representation.

<h2>Why?</h2>

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

h(t)=-16.1t^2 + 150\\0=-16.1t^2 + 150\\16.1t^2=150\\t^2=\frac{150}{16.1}=9.32\\t=+-\sqrt{9.32}=+-3.05\\t1=3.05\\t2=-305

So, discarding the negative value, we can use the possitive value to find the correct graphic representation.

To find the correct graphic representation we must take into consideration the following:

- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.

From the given quadratic (or parabola) equation we have:

a=-1\\b=0\\c=150

So, since the coefficient of the quadratic term is negative, the parabola opens downward.

- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)

- We are looking for a parabola which y-axis intercept is equal to 150.

Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.

Have a nice day!

8 0
3 years ago
Read 2 more answers
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