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zvonat [6]
3 years ago
9

Find the vertex of the parabola y = 8x2.

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

vertex is at (0,0)

Step-by-step explanation:

Find the vertex of the parabola y = 8x2.

I assume you meant   y =  8* x^2

this can be compared to the general vertex form  y = a (x - h)^2 + k

where vertex at  (h, k)

so then...

h =0  and k = 0 here

vertex is at (0,0)

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Which expressions correctly represent the area of the triangle XYZ?
Evgen [1.6K]

Answer:

Options (2) and Option (1)

Step-by-step explanation:

Area of the ΔXYZ = \frac{1}{2}(\text{Base})(\text{Height})

                              = \frac{1}{2}(XZ)h

                              = \frac{1}{2}(18)h

By applying sine rule in the ΔYPZ,

sin(38°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

sin(38°) = \frac{h}{14}

h = 14[sin(38°)]

Therefore, area of the given triangle = \frac{1}{2}(18)(14)sin(38)

By applying sine rule in ΔYPZ,

sin(58°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

sin(58°) = \frac{h}{10}

h = 10sin(58°)

Area of ΔXYZ = \frac{1}{2}(18)(10)sin(58)

Therefore, Options (2) and Option (1) are the correct options.

6 0
3 years ago
What is the area of the circle given the radius 9. use 3.14
xxMikexx [17]

Answer:

254.5

Step-by-step explanation:

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4 0
3 years ago
Find the area, help please
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Step-by-step explanation:

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remember- a= 1/2 b X h

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3 years ago
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aniked [119]
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So A, C, D
7 0
3 years ago
Read 2 more answers
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