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zvonat [6]
3 years ago
9

Find the vertex of the parabola y = 8x2.

Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

vertex is at (0,0)

Step-by-step explanation:

Find the vertex of the parabola y = 8x2.

I assume you meant   y =  8* x^2

this can be compared to the general vertex form  y = a (x - h)^2 + k

where vertex at  (h, k)

so then...

h =0  and k = 0 here

vertex is at (0,0)

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given the function f(x)=-x^2+8x+9, state whether the vertex the represents a maximum or minimum point for the function
olga_2 [115]
If you had
ax^2+bx+c
a is the leading term
when a>0, the parabola opens up and therfor has a minimum point and no max since it goes up infinitely

when a<0, the parabola opens down and therefor has a maximum point and not min since it goes down infinitely

-x^2+8x+9
-1<0
opens down
has max
vertex=max
3 0
4 years ago
Read 2 more answers
Question 3 (5 points)<br> (-1) + 5 -(-6) - 5 =<br> A) -3<br> B) 0<br> C) 5<br> D) -2.
galben [10]

Answer:

5

Step-by-step explanation:

-1+5+6-5

-1-5+5+6

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5

4 0
4 years ago
Brainly i need help on this question pls look at the image k12
lara31 [8.8K]
<h3>Answers:</h3>

1% of 300 is <u>    3     </u>

So 64% of 300 is <u>     192    </u>

========================================

Further explanation:

To take 1% of 300, we just chop off the extra zeros. So that's how I got 3.

To go from 1% to 64%, that's a jump of "times 64". Meaning you multiply that '3' by 64 to get 64*3 = 192.

Notice that 192/300 = 0.64 = 64% to confirm the answer.

5 0
2 years ago
I need help I will give you 15 points
azamat
It’s the first one because the parabola is open
3 0
3 years ago
Read 2 more answers
Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B63%20%5Ctimes%2063%7D%20" id="TexFormul
umka21 [38]

Answer:

  • ± 63

Step-by-step explanation:

  • \sqrt{63*63} = \sqrt{63^2} = ± 63
5 0
3 years ago
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