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Evgesh-ka [11]
3 years ago
8

Can anyone help me with this please.

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0
All you need to do is length x width x height 8x9x5 divided by 2
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What is an equation of the line that passes through the point (-6,7) and is perpendicular to the line
Temka [501]

The equation of line perpendicular to given line through (-6,7) is:

y=\frac{1}{6}x+8

Further explanation:

Given equation of line is:

6x+y=3\\y= -6x+3

The co-efficient of x is the slope of given line.

Let m1 be the slope of given line

and

m2 be the slope of line perpendicular to given line

Then

m_1=-6

Product of slopes of perpendicular lines is -1

m_1*m_2 = -1\\-6*m_2=-1\\m_2=\frac{-1}{-6}\\m_2=\frac{1}6}

The equation of new line can be written as:

y=m_2x+b\\

Putting m2

y=\frac{1}{6}x+b

To find the value of b, we will put (-6,7) in equation

7=\frac{1}{6}(-6)+b\\7=-1+b\\b=7+1\\b=8

Putting the values of b and m in general equation

y=\frac{1}{6}x+8

Keywords: Slope, Point-slope form, perpendicular lines

Learn more about perpendicular lines at:

  • brainly.com/question/12941985
  • brainly.com/question/4152194

#LearnwithBrainly

5 0
3 years ago
Approximate the value of square root of 110 to the nearest hundred
S_A_V [24]
10.49 i belive is the answer
8 0
3 years ago
Read 2 more answers
The cost of four tickets is $32. Write and solve an<br>equation to find the cost of one ticket.​
spayn [35]

Answer:

The question wants us to find the cost of 1 ticket, and the cost of FOUR tickets is $32 meaning our question will be:

What is the cost of 1 ticket, if FOUR tickets cost $32?

And our SHOULD be either:

$4 OR $8.

( COULD NOT GIVE BEST ANSWER DUE TO LACK OF INFORMATION )

3 0
3 years ago
What is the range of the given function?
Paladinen [302]

{x | x = –5, 1, 4, 6}  

8 0
3 years ago
Read 2 more answers
If the class mark and class size of the class
Gemiola [76]

Answer:

The class interval is: 20-30

Step-by-step explanation:

Let l be the lower class limit and u be the upper class limit.

Then according to given statement that class mark is 25

\frac{l+u}{2} = 25\\l+u = 50\ \ \ Eqn\ 1

And

Class size is 10

So, the second equation will be:

u-l = 10\ \ \ \ Eqn\ 2

Adding equation 1 and 2

l+u+u-l = 50+10\\2u = 60\\\frac{2u}{2} = \frac{60}{2}\\u = 30

Now putting u =30 in equation 1

l+u = 50\\l+30 = 50\\l = 50-30\\l = 20

A class interval is written in the form that lower limit comes first and upper limit comes second.

So,

20-30

Hence,

The class interval is: 20-30

7 0
3 years ago
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