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3 years ago

Q2. Admission to a carnival is $8.00. You allow $5.00 for lunch and $3.00 for a snack. Each ride is $2.50.

Mathematics

1 answer:

In-s [12.5K]3 years ago

6 0

You can go on 9 rides, and will have $1.50 left over.
you can make 13 phone calls, and will have $0.15 left over

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What is 482.073 expressed in word form?

____ [38]

Four hundred eighty two point seventy three tenths

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3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

3 years ago

Algebra 1 Grade 9

Whitepunk [10]

You are describing where I live only that temperature is a bit low. I'm sorry to say it is neither one.

t_daily = t_average +/- 5

The highest temperature would be

t_daily = t_average + 5

t_daily = 1 + 5

t_daily = 6

================

The Lowest temperature would be

t_daily = t_average - 5

t_daily = 1 - 5

t_daily = - 4

Sounds about right for December.

6 0

3 years ago

A(n) ______ is the common side of two consecutive angles in a polygon.2.A statement you can probe and then use as a reason in la

Nikolay [14]

An ??????

Well to figure this out, we will use mathematics. You do 90% of the an and then do 39 which is close to 90 and then because it has 9 in the number that is given. So, 213 is incorrect. 90% of the things like 213, = 39. And if it equals 39, then here comes 90. 90 comes in as a number to help, but 213 does to. So we will divide the number 9. 9 = 2, and since 213 has the first digit 2 in the number, that means that the answer is An number that equals 2 is the common side of two consecutive angles in a polygon.

Just a answer!

4 0

3 years ago

Read 2 more answers

Help please do at 11

Bumek [7]

Answer:

Step-by-step explanation:

area = $\pi$ $r^{2}$ so it's $\pi$ $7^{2}$ = 153.938... $cm^{2}$