Question

The curve with equation y2 = x3 + 3x2 is called the tschirnhausen cubic. find an equation of the tangent line to this curve at the point (1, 2). y =

Answer 1

First find the slope, take derivative of both sides with respect to x.  
2y dy/dx=3x^2+6x
solve for dy/dx
dy/dx=[3x^2+6x]/2y
plug in given vales of (1,2(
dy/dx=9/4

now you have everything you need to plug into point slope form
y-2=(9/4)(x-1)
answer is y=(9/4)x+(1/4)