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Anna [14]
2 years ago
5

What is the period of the sinusoidal function

Mathematics
2 answers:
umka21 [38]2 years ago
8 0
The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π. So, a coefficient of b=1 is equivalent to a period of 2π. To get the period of the sine curve for any coefficient b, just divide 2π by the coefficient b to get the new period of the curve.
rodikova [14]2 years ago
3 0

Answer:

The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π. So, a coefficient of b=1 is equivalent to a period of 2π. To get the period of the sine curve for any coefficient b, just divide 2π by the coefficient b to get the new period of the curve.

Step-by-step explanation:

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Choose the graphs that indicate equations with no solution
Sholpan [36]

Answer:

A and E

Step-by-step explanation:

Given

Graphs A to E

Required

Which do not have solutions

When there are no point of intersection between lines and/or curves of a graph, then such graph has no solution.

Using the above description as a yard stick, the first (A) and the last (E) graph have no solution.

8 0
2 years ago
What’s this question
shusha [124]

Multiply the first equation by -1

-3x-y=-4

2x+y=5

Add them up

-x=1

So x=-1

And y=7

So the first option is correct

8 0
3 years ago
A salesman earns a Commission of $630 for selling $3050 in merchandise
agasfer [191]

Answer:

ok so lets find what percentage 630 is of 3050

630/3050=0.20655737704

so about 20.7%

Hope This Helps!!!

7 0
2 years ago
Louisa ran at an average speed of five miles per hour along an entire circular park path. Calvin ran along the same path in the
docker41 [41]

Answer:

15 miles

Step-by-step explanation:

Let x be the miles in the circular park path, t_{L} the time Louisa takes to finish and t_{C} the time Calvin takes to finish both in hours.

Then x, the longitude is equal to the velocity times the time used to finish. So

x=5t_{L}

x=6t_{C}

And the difference between Louisa's time and Calvin' time is 30 minutes, half an hour. So:

t_{C}=t_{L}-0.5

Three equations, three unknowns, the system can be solved.

Equalizing the equation with x :

5t_{L}=6t_{C}

In this last equation replace t_{C}  with the other equation and solve:

5t_{L}=6(t_{L}-0.5)\\ 5t_{L}=6t_{L}-3\\ 3=6t_{L}-5t_{L}\\ 3=t_{L}\\ t_{L}=3

With Louisa's time find x:

x=5t_{L}\\ x=5(3)\\ x=15

7 0
3 years ago
A square pyramid is shown below:
madreJ [45]
Let Surface Area A, a the base edge and h the height:

A = a²+2a√(a²/4+h²)

h=?

pythagorean theorem:

h²=c²-a²

h=√(c²-a²)

h=√(8²-(.7/2)²)= 8

plug it in the above equation A= 11.7ft²

So A is correct







8 0
3 years ago
Read 2 more answers
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