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3 years ago

5

What is the period of the sinusoidal function

2 answers:

umka21 [38]3 years ago

8 0

The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π. So, a coefficient of b=1 is equivalent to a period of 2π. To get the period of the sine curve for any coefficient b, just divide 2π by the coefficient b to get the new period of the curve.

rodikova [14]3 years ago

3 0

Answer:

The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π. So, a coefficient of b=1 is equivalent to a period of 2π. To get the period of the sine curve for any coefficient b, just divide 2π by the coefficient b to get the new period of the curve.

Step-by-step explanation:

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The volume of a rectangular prism, in cubic meters, is given by the expression x to the 3rd power

nydimaria [60]

Answer:

power of 3

Step-by-step explanation:

that formula of rectangular prism V=L×b×h when all of number are in meter will not convert if the number of cubic are not all meter must convet to be in meter by dividing by 10, 100 or 1000

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2 years ago

Find three consecutive even integers, such that

SIZIF [17.4K]

Answer:

8,10 ,12

Step-by-step explanation:

x

x+2

x+4

5x-18 =x+2 + x+4

5x-18=2x+6

3x=24

x=8

8*5=40 40-18= 22

10+12 = 22

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3 years ago

How would you read the expression, 4^3? CLEAR CHECK four to the third power four to the three power three-fourths four-thirds

Vlad1618 [11]

Answer:

4 to the power of three

Step-by-step explanation:

5 0

3 years ago

Write an equation of the line with a slope of 2/3<br> and y -intercept of -8

Naddik [55]

Y = 2/3x + -8 or y = 2/3x - 8

4 0

3 years ago

Read 2 more answers

Write a system of linear inequalities so the points (1, 2) and (4, -3) are solutions of the system, but the point (-2, 8) is not

Verizon [17]

Answer: $\left \{ {{y\leq -\frac{5}{3}x + \frac{11}{3}} \atop {y < 8}} \right$

<u>Step-by-step explanation:</u>

(1, 2) and (4, -3)

First, find the slope (m): $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

m = $\frac{-3-2}{4-1}$

= $-\frac{5}{3}$

Next, choose ONE of the points and input the point and slope into the Point-Slope formula: y - y₁ = m(x - x₁)

y - 2 = $-\frac{5}{3}$ (x - 1)

y - 2 = $-\frac{5}{3}x$ + $\frac{5}{3}$

y = $-\frac{5}{3}x$ + $\frac{11}{3}$

Then, determine which inequality symbol will result in (-2, 8) being False (since it is not a solution):

y ___ $-\frac{5}{3}x$ + $\frac{11}{3}$

8 ___ $-\frac{5}{3}(-2)$ + $\frac{11}{3}$

8 ___ $\frac{1}{3}$

8 > $\frac{1}{3}$

so ≤ makes the statement False

⇒ y ≤ $-\frac{5}{3}x$ + $\frac{11}{3}$

****************************************************************

If you need a "system" of inequalities, then you need another equation.

There are infinite possibilities. Graph the points to see what works.

y < 8 or x > -2 are two examples.

---> I just realized that the system can be simpler than what I did above:

$\left \{ {{x>-2} \atop {y < 8}} \right$

4 0

3 years ago