<span>Area = (1/2)(533 ft)(525 ft) sin(53) = 111739 square feet</span>
Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .
Answer:
it is data that you can see or describe such as he is a boy
Step-by-step explanation: