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GREYUIT [131]
3 years ago
10

Which point would not be a solution to the system of linear inequalities shown

Mathematics
1 answer:
Strike441 [17]3 years ago
6 0

-12,3 ...................................

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The theoretical probability of selecting a consonant at random from a list of letters in the alphabet is 21/26. Wayne opens a bo
marysya [2.9K]

Answer:

You need a corpus of text. It usually gathers text from passages, chapters, or sections of a book.

6 0
3 years ago
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What are the values that satisfy the trigonometric equation for: 0 ≤ q ≤ 2Π ?
bagirrra123 [75]
Answer: 0, π, 2π

Nevertheless, that is not an option. I see two possibilities: 1) the options are misswirtten, 2) the domain is not well defined.

If the domain were 0 ≤ θ < 2π, then 2π were excluded of the domain ant the answer would be 0, π.

Explanation:

1) The first solution, θ = 0 is trivial:

sin (0) - tan (0) = 0

0 - 0 = 0

2) For other solutions, work the expression:

sin(θ) + tan (-θ) = 0 ← given

sin (θ) - tan(θ) = 0 ← tan (-θ) = tan(θ)

sin(θ) - sin (θ) / cos(θ) = 0 ← tan(θ) = sin(θ) / cos(θ)

sin (θ) [1 - 1/cos(θ)] = 0 ← common factor sin(θ)

⇒ Any of the two factors can be 0

⇒ sin (θ) = 0 or (1 - 1 / cos(θ) = 0,

sin(θ) = 0 ⇒ θ = 0, π, 2π

1 - 1/cos(θ) = 0 ⇒ 1/cos(θ) = 1 ⇒ cos(θ) = 1 ⇒ θ = 0, 2π

⇒ Solutions are 0, π, and 2π

In fact if you test with any of those values the equation is checked. The only way to exclude one of those solutions is changing the domain.
7 0
3 years ago
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Help me with the triangle area please
dexar [7]

Answer:

15 m ^2

Step-by-step explanation:

3 x 10 is 30

divide that by 2 since the triangle can fit in half of the rectangle shape

you will get 15

7 0
3 years ago
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In a random sample of 200 Americans, 51% said they favor building more nuclear power plants. In a random sample of 150 French, 4
Varvara68 [4.7K]

Answer:

Yes, there is enough evidence to say the proportions are the same.

Step-by-step explanation:

Null hypothesis: The proportions are the same.

Alternate hypothesis: The proportions are not the same.

Data given:

p1 = 51% = 0.51

n1 = 200

p2 = 48% = 0.48

n2 = 150

pooled proportion (p) = (n1p1 + n2p2) ÷ (n1 + n2) = (200×0.51 + 150×0.48) ÷ (200 + 150) = 174 ÷ 350 = 0.497

Test statistic (z) = (p1 - p2) ÷ sqrt[p(1-p)(1/n1 + 1/n2) = (0.51 - 0.48) ÷ sqrt[0.497(1-0.497)(1/200 + 1/150)] = 0.03 ÷ 0.054 = 0.556

The test is a two-tailed test. At 0.10 significance level the critical values -1.645 and 1.645

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.556 falls within the region bounded by the critical values.

8 0
3 years ago
Factorise fully 12x - 8​
mestny [16]

Answer:

4(3x-2)

Step-by-step explanation:

Have a great day :)

5 0
3 years ago
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