Step-by-step explanation:
3(4x - 2) = 12x - 6
12x - 6 = 12x - 6
that is always true, no matter what value we pick for x.
so, this has infinite many solutions.
3(4x - 2) = -12x - 6
12x - 6 = -12x - 6
24x = 0
x = 0
this has one solution.
-3(4x - 2) = -12x - 2
-12x - 6 = -12x - 2
-6 = -2
this is never true, no matter what value we pick for x.
so, this has no solution at all.
X^2+4x-12=0
(x+6)(x-2)=0
X can equal -6 and 2.
x=-6
x=2
Given:
The x and y axis are tangent to a circle with radius 3 units.
To find:
The standard form of the circle.
Solution:
It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.
We know that the radius of the circle are perpendicular to the tangent at the point of tangency.
It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).
The standard form of a circle is:

Where, (h,k) is the center of the circle and r is the radius of the circle.
Putting
, we get


Therefore, the standard form of the given circle is
.
Answer:
Prime factorization: 825 = 3 × 5 × 5 × 11, which can be written 825 = 3 × 5² × 11.
Step-by-step explanation:
Hope this helps!