Answer:
- <em>To solve these first swap x and y, solve for y and name it inverse function</em>
3. <u>y = -8x + 2</u>
- x = -8y + 2
- 8y = -x + 2
- y = -x/8 + 2/8
- y = -(18)x + 1/4
f⁻¹(x) = -(18)x + 1/4
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4.<u> y = (2/3)x - 5</u>
- x = (2/3)y - 5
- (2/3)y = x + 5
- y = (3/2)x + (3/2)5
- y = 1.5x + 7.5
f⁻¹(x) = 1.5x + 7.5
-----------------------------------------
5. <u>f(x) = 2x² - 6</u>
- x = 2y² - 6
- 2y² = x + 6
- y² = 1/2x + 3
- y =
![\sqrt{1/2x + 3}](https://tex.z-dn.net/?f=%5Csqrt%7B1%2F2x%20%2B%203%7D)
f⁻¹(x) = ![\sqrt{1/2x + 3}](https://tex.z-dn.net/?f=%5Csqrt%7B1%2F2x%20%2B%203%7D)
-----------------------------------------
6. <u>y = (x - 3)²</u>
- x = (y - 3)²
= y - 3- y = 3 +
![\sqrt{x}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D)
f⁻¹(x) = 3 + ![\sqrt{x}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D)
I think The answer is 22.5
Answer:
51.92 square inches
Step-by-step explanation:
Area of a circle = (pi)(r^2)
if the diameter is 7, the radius is 3.5
A = 3.14 x 3.5
A = 10.99 cm^2 for one cookie
10.99 x 12 for a dozen = 131.88 cm^2
converting cm to inches, you divide by 2.54
131.88/2.54 = 51.92 square inches.
LMK if you have questions.
Answer:
0.1971 ( approx )
Step-by-step explanation:
Let X represents the event of weighing more than 20 pounds,
Since, the binomial distribution formula is,
![P(x)=^nC_r p^r q^{n-r}](https://tex.z-dn.net/?f=P%28x%29%3D%5EnC_r%20p%5Er%20q%5E%7Bn-r%7D)
Where, ![^nC_r=\frac{n!}{r!(n-r)!}](https://tex.z-dn.net/?f=%5EnC_r%3D%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D)
Given,
The probability of weighing more than 20 pounds, p = 25% = 0.25,
⇒ The probability of not weighing more than 20 pounds, q = 1-p = 0.75
Total number of samples, n = 16,
Hence, the probability that fewer than 3 weigh more than 20 pounds,
![P(X](https://tex.z-dn.net/?f=P%28X%3C3%29%20%3D%20P%28X%3D0%29%2BP%28X%3D1%29%2BP%28X%3D2%29)
![=^{16}C_0 (0.25)^0 (0.75)^{16-0}+^{16}C_1 (0.25)^1 (0.75)^{16-1}+^{16}C_2 (0.25)^2 (0.75)^{16-2}](https://tex.z-dn.net/?f=%3D%5E%7B16%7DC_0%20%280.25%29%5E0%20%280.75%29%5E%7B16-0%7D%2B%5E%7B16%7DC_1%20%280.25%29%5E1%20%280.75%29%5E%7B16-1%7D%2B%5E%7B16%7DC_2%20%280.25%29%5E2%20%280.75%29%5E%7B16-2%7D)
![=(0.75)^{16}+16(0.25)(0.75)^{15}+120(0.25)^2(0.75)^{14}](https://tex.z-dn.net/?f=%3D%280.75%29%5E%7B16%7D%2B16%280.25%29%280.75%29%5E%7B15%7D%2B120%280.25%29%5E2%280.75%29%5E%7B14%7D)
![=0.1971110499](https://tex.z-dn.net/?f=%3D0.1971110499)
![\approx 0.1971](https://tex.z-dn.net/?f=%5Capprox%200.1971)