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MAXImum [283]
3 years ago
13

A circle has a radius of 1 cm. How does the circumference of the circle compare to the area? Drag and drop a phrase to correctly

complete the sentence.
The circumference is the area

A)greater than B)less than C)equal to
Mathematics
1 answer:
Lana71 [14]3 years ago
7 0
THE ANSWER IS GREATER THAN I TOOK THIS LESSON!
You might be interested in
Without multiplying, order the following products from least to greatest. 23* 2/2 23* 1/4 23* 13/5
Romashka-Z-Leto [24]
Answer:

From least to greatest

23* 1/4, 23* 2/2, 23* 13/5

Explanation

In order to do this without multiplication, place the fractions in ascending order.

The denominators of these fractions have 20 as a common multiple.

2/2 • 10 = 20/20

1/4 • 5 = 5/20

13/5 • 4 = 52/20

From this it logically follows that the fractions in ascending order are:

1/4, 2/2, 13/5

Therefore the products in ascending order are:

23* 1/4, 23* 2/2, 23* 13/5



7 0
3 years ago
The shapes show that there are 4 squares for every
mina [271]

Answer:

8

Step-by-step explanation:

6 0
3 years ago
Pls help will give brainlest.
Arada [10]

2,400 in.³

I Love Maths :)

7 0
3 years ago
Read 2 more answers
If CP=Rs. 1200 and loss =10%, find loss amount.​
goldfiish [28.3K]

Answer:

lost 120

Step-by-step explanation:

10% of 1200 is 120 so you subtract 120 from 1200

7 0
3 years ago
Read 2 more answers
HELP ASAP ...........
dedylja [7]

Answer:

A

Step-by-step explanation:

Given

y - 2x - 8 = 0 ( add 2x + 8 to both sides )

y = 2x + 8 → (1)

y² + 8x = 0 → (2)

Substitute y = 2x + 8 into (2)

(2x + 8)² + 8x = 0 ← expand left side using FOIL and simplify

4x² + 32x + 64 + 8x = 0

4x² + 40x + 64 = 0 ( divide through by 4 )

x² + 10x + 16 = 0 ← in standard form

(x + 8)(x + 2) = 0 ← in factored form

x + 8 = 0 ⇒ x = - 8

x + 2 = 0 ⇒ x = - 2

Substitute these values into (1) for corresponding values of y

x = - 8 : y = 2(- 8) + 8 = - 16 + 8 = - 8 ⇒ P (- 8, - 8)

x = - 2 : y = 2(- 2) + 8 = - 4 + 8 = 4 ⇒ Q (- 2, 4 )

Calculate the length of PQ using the distance formula

PQ = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = P (- 8, - 8) and (x₂, y₂ ) = Q (- 2, 4 )

PQ = \sqrt{(-2-(-8))^2+(4-(-8))^2}

      = \sqrt{(-2+8)^2+(4+8)^2}

       = \sqrt{6^2+12^2}

       = \sqrt{36+144}

       = \sqrt{180}

       = \sqrt{36(5)}

       = \sqrt{36} × \sqrt{5}

        = 6\sqrt{5} → A

8 0
2 years ago
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