Answer:
-5/8a - 2.8b
Step-by-step explanation:
-3/8a + 3.2b + (-6b) - 1/4a
=> -3/8a + 3.2b + (-6b) - 2/8a
=> -5/8a + 3.2b - 6b
=> -5/8a - 2.8b
Therefore, -5/8a - 2.8b is the solution to your problem.
Hoped this helped.
Answer:
$295.01
Step-by-step explanation:
Using the compounding continuously formula, we are looking for A. We have that P = 190; r = .11 (always use the decimal form of the rate!); and t = 4. Filling in we have:
Simplifying that multiplication:
.
On your calculator, raise e to the .44 power to get
A = 190(1.552707219) and
A = $295.01
Answer:
Step-by-step explanation:
What this question is asking of you is what is the greatest common divisor of 12 and 15. Or, what is the biggest number that divides both 12 and 15.
in order to find this we have to split each number into it's prime components.
for 12 they are 2,2 and 3 (
2
⋅
2
⋅
3
=
12
)
and for 15 they are 3 and 5 (
3
⋅
5
=
15
)
Out of those two groups (2,2,3) and (3,5) the only thing in common is 3, so 3 is the greatest common divisor. That tells us that the greatest number of groups that can exist and have the same number of girls and the same number of boys for each group is 3.
Now to find out how many girls and boys there are going to be in each group we divide the totals by 3, so:
12
3
=
4
girls per group, and
15
3
=
5
boys per group.
(just as a thought exercise, if there were 16 boys, the divisors would have been (2,2,3) and (2,2,2,2), leaving us with 4 groups [
2
⋅
2
] of 3 girls [12/4] and 4 boys [16/4] )
Answer: 86
Step-by-step explanation:
Answer:
The answer is below
Step-by-step explanation:
Speed is the time rate of change of velocity, it is the ratio of distance to time.
Mr. Fowles runs at a steady 4.2 miles per hour. The time taken to cover 26 miles is:
speed = distance / time
time = distance / speed = 26 / 4.2 = 6.19 hour
I run at 3 miles per hour. I was given 3 mile lead, so the remaining distance is 23 miles (26 - 3). The time needed to complete the 23 miles is:
time = distance / speed = 23 / 3 = 7.67 hour
a) Let d be the distance Mr Fowles catches me. Hence:
time = (d + 3)/4.2; also time = d/3
(d + 3)/4.2 = d/3
3d + 9 = 4.2d
1.2d = 9
d = 7.5 miles
He would catch me at 10.5 (7.5 + 3) miles from the starting point.
b) Mr. fowles finishes after 6.19 hour. At that time, the distance is have covered is:
distance = 6.19 * 3 mi/hr = 18.57 mile
Distance behind = 23 mile - 18.57 = 4.43 mile
c) time longer = 7.67 hour - 6.19 hour = 1.48 hour
