The temperature (in k) at which the density of this liquid will be equal to 1.183 g/cm³ is; 639.6 K
<h3>How to find the temperature from density?</h3>
We are given the formula for density as;
D = 1.246 g/cm³/(1 + 8.324 * 10⁻⁵ K⁻¹ × T)
Where D is density and T is absolute temperature (In K).
If we want a density of 1.183 g/cm³, then we have;
1.183 = = 1.246 g/cm³/(1 + 8.324 * 10⁻⁵ K⁻¹ × T)
Cross multiply to get;
1.183 + (1.183 * 8.324 * 10⁻⁵ * T) = 1.246
1.183 + 0.985 * 10⁻⁴T= 1.246
0.985 * 10⁻⁴T = 1.246 - 1.183
T = 0.063/( 0.985 * 10⁻⁴)
T = 639.6 K
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Walter will have walked 1.05 miles.
To find the missing piece on the right side, we need to set up and solve the following proportion.
0.2 / 0.5 = 0.3 / x
x = 0.75
Now, that we know the 2 pieces on the right side, just add them together.
0.3 + 0.75 = 1.05 miles
Answer:
First number line
Step-by-step explanation:
-6 means 6 to the left, and subtracting -8 to it means 8 to the right.
20 feet
Area of a triangle:
1/2•base•height
1/2•8•5= 20
Answer:
(A) 2/3 [√(4-4x)]^3
(B) 2/3 [√(4-x)]^3
Step-by-step explanation:
Integrating the functions,
(A) Any function in square root is equal to or same as the function raised to the power of 1/2
To integrate, add 1 to the power of the function. That's 1/2 + 1 = 3/2
Divide the function by this new power 3/2. This implies multiplying the function by the inverse of 3/2. The inverse of 3/2 is 2/3.
Also, when a function is raised to the power of a fraction instead of a whole number, you take the 'denominator' root of the function, and then raise the function to the power of the numerator.
Here, the denominator is 2, so you take the square root of the function, and raise the function to the power of 3
So the integral of Y = √[4-4x] is
2/3 [√(4-4x)]^3
(B) In like manner, the integral of
Y = √[4-x] is
2/3 [(√4-x)]^3
