Answer:
−
10
x
^3
−
4
x
^2
+
4
x
+
3
Step-by-step explanation:
You would probably have to measure it greatest distance by ur least distance and subtract or add
Answer:
x=
Step-by-step explanation:
Q= illumination
I = intensity
Q= I/d^2
Q_total = ![\frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}](https://tex.z-dn.net/?f=%5Cfrac%7BI_1%7D%7Bd_1%5E2%7D%2B%5Cfrac%7BI_2%7D%7Bd_2%5E2%7D)
= ![\frac{I}{x^2}+\frac{2I}{(16-x)^2}](https://tex.z-dn.net/?f=%5Cfrac%7BI%7D%7Bx%5E2%7D%2B%5Cfrac%7B2I%7D%7B%2816-x%29%5E2%7D)
now Q' = 0
⇒I![{-\frac{2}{x^3}}+\frac{4}{(16-x)^3}](https://tex.z-dn.net/?f=%7B-%5Cfrac%7B2%7D%7Bx%5E3%7D%7D%2B%5Cfrac%7B4%7D%7B%2816-x%29%5E3%7D)
x=![\frac{16}{\sqrt[3]{2}+1 }](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B%5Csqrt%5B3%5D%7B2%7D%2B1%20%7D)
[/tex]![\frac{1}{x^3} = \frac{2}{(16-x)^3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%5E3%7D%20%3D%20%5Cfrac%7B2%7D%7B%2816-x%29%5E3%7D)
x=
is the required point
<span>7 no encaja en 4, por lo que la respuesta sería cero 7 ajustes en 4, cero veces</span>
(f+g) (n) = (–5n +1 ) + (- 6n +2) = –11n +3
(f+g) (n) = –11n +3
(f+g) (–2) = – 11 (–2) +3 = 22 +3 = 25
I hope I helped you^_^