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qwelly [4]
3 years ago
8

What is the volume of a cylinder with a radius of 3 cm and a height of 5 cm?

Mathematics
2 answers:
marusya05 [52]3 years ago
6 0

Answer

Volume ≈ 141.37cm³

PSYCHO15rus [73]3 years ago
5 0

Answer:

141.3 cm³

Step-by-step explanation:

V=πr2h=π·32·5≈141.37167cm³

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Find the number of degrees in each rotation shown below.
ZanzabumX [31]

Answer:

5

Step-by-step explanation:

8 0
2 years ago
Could someone answer and explain these please? Thank you!
Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

x=(10 \times t)+(1 \times u)

x=10t+u

The two digit number 'y' is obtained by reversing the digits of x.

So, y=(10 \times u)+(1 \times t)

y=10u+t

Now, the value of x-y is expressed as:

x-y=(10t+u)-(10u+t)

x-y=10t+u-10u-t

x-y=9t-9u

x-y=9(t-u)

So, 9(t-u) is equivalent to (x-y).

Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = \frac{a}{1-r}

Since, the sum of the given infinite geometric series = 200

Therefore,\frac{a}{1-r}=200

Since, r=0.15 (given)

\frac{a}{1-0.15}=200

\frac{a}{0.85}=200

a=0.85 \times 200

a=170

The nth term of geometric series is given by ar^{n-1}.

So, second term of the series = ar^{2-1} = ar

Second term = 170 \times 0.15

= 25.5

So, the second term of the geometric series is 25.5






Step-by-step explanation:


8 0
3 years ago
Can someone help me please?
marishachu [46]
(6x + 30)+(2x+6)= 180
8x +36= 180
8x= 144
X= 18
So 2x+6 = 42
And 6x+30 = 138
8 0
3 years ago
Help me find the answer <br>Tan 0 and Cot O ​
vesna_86 [32]

Answer:

Step-by-step explanation:

we can say the angle is also +45° going in the clock wise direction.  so take Tan(45)= 1

Cot(45) = 1

b/c  Tan(45) = Sin(45) /Cos(45) = (\sqrt{2}/2) / (\sqrt{2}/2)   ofc that's just 1

b/c Cot(45) = Cos(45) / Sin(45) , which is the same as above 1

3 0
3 years ago
Consider the parametric curve:
11Alexandr11 [23.1K]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}=\dfrac{4\sec t\tan t}{3\sec^2t}=\dfrac43\sin t

When t=\pi, we have

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{t=\pi}=\dfrac43\sin\pi=0

7 0
3 years ago
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