Answer:
I would write a question about relationships between predators and prey of a given ecosystem.
Explanation:
An example question is:
a.) "Draw a predator-prey graph that shows the relationship between lions and zebras."
b.) "Explain the trends of the above graph with regard to increase and decrease of the prey of predators."
I hope that made sense :)
Good luck.
Small, electron-lucent vesicles known as synaptic vesicles (SVs) are grouped at presynaptic terminals. They hold neurotransmitters and exocytosis, which is stimulated by calcium, releases them. After exocytosis, SVs are formed locally at the terminals.
- From the presynaptic cell with synaptic vesicles to the postsynaptic cell with neurotransmitter receptors, a signal always moves in one direction across the chemical synapse.
- The correct routing of nerve signals throughout the body is guaranteed by this one-way communication.
- A signal is transmitted from one neuron—the presynaptic, or sending, neuron—to another neuron—the postsynaptic, or receiving, neuron—at the synapse, increasing or decreasing the likelihood that the postsynaptic neuron will fire its own action potential.
- The stimulation causes a sensory neuron to go into an action potential, which alters the motor neuron's potential.
- Excitatory because it tends to depolarize the cell, this potential is known as an excitatory postsynaptic potential (EPSP).
learn more about synaptic vesicles here:brainly.com/question/5865840
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The Hardy-Weinberg equation is as follows:


Where:
(convert all % to decimals)
p= homozygous dominant
q= homozygous recessive
pq= heterozygous
While you did not specify whether the 0.2 frequency was for dominant or recessive, we can still figure out the answer.
Using the 1st equation, we can solve for the other dominant/recessive frequency:
1-0.2=0.8
Meaning that:
p= 0.8 & q=0.2
If the heterozygouz frequency is 2pq, then it becomes a simple "plug & chug" sort of approach.
2(0.8)(0.2)= 2(0.16)= 0.32
So, the heterozygous frequency would be:
0.32
Hope this helps!
A.The genotype frequencies can be determined by dividing the number of individuals with a genotype by the total number all the individuals.
FF genotype frequency:
98÷200=0,49. There are approximately 5 <span>homozygous dominant mice in 10.
Ff genotype frequency:
84</span>÷200=0,42. There are approximately 4 <span>heterozygous mice in 10.
ff genotype frequency:
18</span>÷200=0,09. There are approximately 1 <span>homozygous recessive mouse in 10.
B.To determine the frequency of an allele we can divide the number of times that the allele appears by the total number of alleles.
F allele frequency:
</span>

<span>=0.7
There are 7 F alleles in 10 random alleles.
f </span>allele frequency:

=0.3
There are 3 f alleles in 10 random alleles.<span>
</span>
The answer is the platelets