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2 years ago

Given the equation y = 3x-5, what is the slope

Mathematics

1 answer:

zzz [600]2 years ago

5 0

Answer:

given the equation y=3x-5 the slope would be 3

Step-by-step explanation:

looking at the equation you can see it is in y=mx+b form. this means that the coefficient next to the x is the slope

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Which numbers are perfect squares? Check all that apply.

Andrew [12]

A perfect square is a number made by squaring a whole number.

Since

$1^2=1;$
$4^2=16;$
$10^2=100,$

numbers 1, 16, 100 are perfect squares. You cannot find such whole number n, that

$2=n^2;$
$18=n^2;$
$32=n^2;$
$44=n^2;$
$94=n^2,$

therefore, numbers 2, 18, 32, 44, 94 are not perfect squares.

Answer: 1, 16, 100.

4 0

2 years ago

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Solve for y in this equation 6( y-1) -9=-5(-3y+5) -3y

saul85 [17]

6(y-1)-9=-5(-3y+5)-3y
6y-6-9=15y-25-3y
6y-15=12y-25
+15. +15
6y=12y-25
+12y +12y
18y=-25
÷18. ÷18
y=-1.38
or -1 19/50

8 0

3 years ago

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Find the GCF of 20 and 30. 02 05 O 10 O 15

vitfil [10]

Answer:

Step-by-step explanation:

10 is the greatest common factor of 20 and 30

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2 years ago

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Question: The stem-and-leaf plot shows the test scores of a science class. Use the plot to answer the question.

Nikitich [7]

The mode of the data is 8

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2 years ago

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The revenue R you receive for selling pizza slices depends on the price p that you charge per slice and is modeled by R =-16p

sp2606 [1]

Answer:

$p \geq 0$

Step-by-step explanation:

Given

$R(p) = -16p^2 + 80p + 5$

Required

Determine the domain of the function

To do this, we need to solve for the vertex, p of the function

$p= \frac{-b}{2a}$

Given the the general form of a quadratic function is:

$y = ax^2 + bx + c$

By comparison, we have:

$a = -16$ $b =80$ $c = 5$

So:

$p= \frac{-b}{2a}$

$p = \frac{-80}{-16 * 5}$

$p = \frac{-80}{-80}$

$p = 1$

Substitute 1 for p in $R(p) = -16p^2 + 80p + 5$

$R(1) = -16(1)^2 + 80(1) + 5$

$R(1) = -16 + 80 + 5$

$R(1) = 69$

This implies that

$(p, R) = (1,69)$

The interpretation of this is that;

For every value of p, there's a corresponding value of R.

However, because p indicates price and it's impossible to have a negative price, we can say that the minimum value of p is 0;

Hence, the domain is

$p \geq 0$

8 0

2 years ago