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Igoryamba
3 years ago
14

P(-2) = 1P(-1) =3 P(1) = 0 P(2) = 4

Mathematics
1 answer:
ratelena [41]3 years ago
8 0

p(-1) p(-2) p(1) p(6)= 4

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Find the magnitude of −3i<br> .
Minchanka [31]

Answer:What is the magnitude of 3i?

3i invested c.

Step-by-step explanation: $182m in Magnitude Software in 2019 to accelerate its global growth ambitions through new product development and investments in sales & marketing, and to build a more integrated enterprise software business.

5 0
2 years ago
For the function f(x) = 5x - 7 answer the following questions:
Elis [28]

Answer:

See below

Step-by-step explanation:

<h3>Given function </h3>
  • f(x) = 5x - 7

<u>Another notation for same function is</u>

  • y = 5x - 7, where 5 is the slope and -7 is the y-intercept
<h3>Questions </h3>

<u>1. Is the function increasing or decreasing? </u>

  • Increasing as x has positive slope

<u>2. What is the y-intercept? </u>

  • y- intercept is -7

<u>3. What is the slope? </u>

  • The slope is 5

<u>4. What is f(-2)? </u>

  • f(-2) = 5(-2) - 7 = - 10 - 7 = -17

<u>5. If f(x) = 0, what is x?</u>

  • f(x) = 0
  • 0 = 5x - 7
  • 5x = 7
  • x = 7/5
  • x = 1.4
8 0
3 years ago
Read 2 more answers
A force of 3 pounds is required to hold a spring stretched 0.6 feet beyond its natural length. how much work (in foot-pounds) is
ioda

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Work done (Wd) =?

<h3>How to determine the spring constant</h3>
  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Spring constant (K) =?

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

<h3>How to determine the work done</h3>
  • Spring constant (K) = 5 pound/foot
  • Extention (e) = 0.7 feet
  • Work done (Wd) =?

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

5 0
1 year ago
What is 3/4 x 9 = <br><br>helppppppppppppppp​
anzhelika [568]
The answer is 6.75 or 27/4
4 0
3 years ago
Read 2 more answers
The volume of a right square pyramid is 80 cubic feet. If the sides of the base are doubled, but the height remains the same, wh
maksim [4K]

Answer:

  320 cubic feet

Step-by-step explanation:

The volume is proportional to the product of the area of the base and the height of the pyramid. When the dimensions of the base are doubled, the area is multiplied by 2² = 4, hence the volume of the pyramid will be multiplied by 4.

  4 × (80 ft³) = 320 ft³

The new volume of the pyramid is 320 cubic feet.

7 0
3 years ago
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