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Tems11 [23]
3 years ago
15

Two perpendicular lines intersect at the origin. If the slope of the first line is .5, what is the equation of the second line?.

.
Mathematics
1 answer:
Sedaia [141]3 years ago
3 0
The origin is at the point (0,0). Therefore, the y-intercept will be 0. For two points to be perpendicular, the slopes must be opposite reciprocals of each other. .5 can be seen as 1/2, so the reciprocal is 2, and it is positive, making that 2 negative. Your equation would be y = -2x. 
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A bag contains yellow marbles in red marbles 65 in total. The number of yellow marbles is five more than four times the number o
antoniya [11.8K]

Answer: there would be 52 yellow marbles

Step-by-step explanation:

Ok we know that there is 65 marbles in total? Right? So then we’d take 65 and think, what could we divide this by and start guessing and estimating numbers. (I guessed 5, one because it’s divisible by 65, two there is 5 times more yellow marbles than red marbles.) So 5 divided by 65 is 13. But, in order to find the amount of yellow marbles, we need to subtract the whole number by the amount of red marbles. (So 65-13 =?) if you subtract that you get 52 yellow marbles.  :)

7 0
3 years ago
If h(x) = 4x – 3 and p(x) = x2 – 3x, find p(-3)<br><br> 18<br> 0<br> -3
navik [9.2K]

Answer: p(-3)=18

Step-by-step explanation:

To find p(-3), you plug -3 into p(x) and solve.

p(-3)=(-3)²-3(-3)               [exponent]

p(-3)=9-3(-3)                    [multiply]

p(-3)=9+9                         [add]

p(-3)=18

Now we found that p(-3)=18.

7 0
3 years ago
Find the slope of the tangent line to the curve f(x)=e^(x) at (0.4,1.49)
almond37 [142]

Answer:

1.49

Step-by-step explanation:

In order to find the slope of the tangent line to a given equation, and in a given point, we need to:

1. Find the first derivative of the given function.

2. Evaluate the first derivative function in the given point.

1. Let's find the first derivative of the given function:

The original function is f(x)=e^{x}

But remeber that the derivative of  e^{x} is  e^{x}

so, f'(x)=e^{x}

2. Let's evaluate the first derivative function in the given point

The given point is (0.4,1.49) so:

f'(x)=e^{x}

f'(0.4)=e^{0.4}

f'(x)=1.49

Notice that the calculated slope of the tangent line is equal to the y-coordinate of the given point because f'(x)=f(x). In conclusion, the slope of the tangent line is equal to 1.49.

8 0
3 years ago
1st one to answer gets brainliest
Vesnalui [34]

Answer:

Step-by-step explanation:

5 0
2 years ago
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1.<br> What is the equation of a circle with center (-5, 8) and radius 9?
miss Akunina [59]

Answer:

Your equation is:

(x−5)2+(y+8)2=92

Expanding from general form you can write this as:

x2−10x+y2+14y+−8=0

Step-by-step explanation:

i think its correct ig don't know sry but i tried hope it helps you ✨

8 0
3 years ago
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