it hasn't been specified which ticket the question's is asking but I'm guessing the price of the adult ones so $30.00
altogether that's two adults and 3 children who all paid a total of $105.00
let's simplify that to algebra
children tickets = c adults tickets = a
3c + 2a = $105.00
we know that 1c is 0.5a because each child ticket is half of an adults one <em>as stated in the question</em>
so in terms of (adults) a: half of 3 meaning 3×0.5= $1.5 meaning 1.5a
so now <em>3c = 1.5a</em>
so we can substitute and have like terms
meaning 1.5a + 2a= $105
3.5a =$105.00
divide by 3.5 on both sides to get a by itself thus the value of a:
a = $30
so each adult tickets cost $30
First list all the factors of 12;
1, 2, 3, 4, 6, 12
now let's see which ones are multiples of 3;
3, 6, 12
so all we have left are numbers 1, 2 and 4.
hope that helps, God bless!
Area of ∆=1/2bh
80yd^2=1/2(b)(10yd)
80yd^2=5yd(b)
80yd^2÷5yd=b
16yd=b
Ok so linear equations come in the form
y = mx + b
B is the y-intercept. In this equation the y intercept is 40. A y- intercept is where the graph crosses the y axis so at the point (0,40) the graph crosses the y axis.
M is the slope which is rise over run so if the slope was 10 (which it is) 10 is equivalent to 10/1 so you move up 10 units for every 1 unit you move across.
So to graph this equation, you would draw your first point at (0,40). For your next point, you would move right one unit, and up 10 units. Draw a point there which would be (1, 50). Hopefully you understand. For going left from the y intercept point, you would move left 1 and down 10.
Actual graph above.
Hope this helps C: