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notsponge [240]
3 years ago
7

6 radians is the same as ____°. Round to the nearest hundredth of a degree.

Mathematics
2 answers:
sladkih [1.3K]3 years ago
6 0

Answer:

343.77°

Step-by-step explanation:

1 radian =  \frac{180}{Pi}°

6 radians will be;

6 ×  \frac{180}{Pi}° =343.7746771 °

Or 343.77° (rounded up to nearest hundredth)

Brums [2.3K]3 years ago
3 0

Answer:

343.77

Step-by-step explanation:

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Let x = 4.<br><br><br><br> What is the value of y in the equation y = 15 + 11 + x?
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Okay so you have to add up 15 and 11 and 4 so your answer is y=30


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An angle is created from points C, A, and B with vertex A. An arc is drawn from point A and intersects rays AC and AB. The inter
Minchanka [31]

Answer:

Bisecting an angle ⇒ answer a

Step-by-step explanation:

* <em>Lets revise the steps of bisecting an angle</em>

- <em><u>How to construct a bisector of angle XYZ</u></em>

1. Open the compass to any width, and place its pin at the angle’s

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   at two points M and N respectively

2. Open the compass to another width and place its pin at M and draw

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3. Without changing the width of the compass place its pin at N and

   draw another arc intersects the arc from M at point Q

4. Join YQ which is the bisector of angle XYZ

* <em>Now lets compare these steps by the steps of the question</em>

∵ The vertex of the angle ABC is A represented by Y

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7 0
3 years ago
The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota
Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

a.

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

b.

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

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