In order to find the value of f(-2), you can plug -2 wherever x is.
f(x) = 6x^2 - 4
f(-2) = 6(-2)^2 - 4
f(-2) = 6(4) - 4
f(-2) = 24 - 4
f(-2) = 20
Thus, the value of f(-2) is 20. Hope this helps! If you have any other questions related to this, let me know.
Answer:
Step-by-step explanation:
Sum: addition
Difference: subtraction
Product: multiplication
Number Sum Difference Product
1, 4 1 + 4 = 5 4 - 1 = 3 1 * 4 = 4
2, 8 2 + 8 = 10 8 - 2 = 6 2 * 8 = 16
Hope this helps!
One of the zeroes would be : x = 1
f (1) = 1^3 + 6(1) ^2 + 3 (1) - 10
f(1) = 1 + 6 + 3 - 10
f (1) = 10 - 10
f (1) = 0
Hope this helps
Answer:
n < 20
Step-by-step explanation:
2n – 1 < 39
Add 1 to each side
2n – 1+1 < 39+1
2n < 40
Divide each side by 2
2n/2 < 40/2
n < 20
Just plug in -3 for x. So it will be -(-3)^+ 1
Which is 3^+1.
I'm confused by your ^ sign I'm not sure if this is supposed to be squared or not...? But just solve/simplify the equation.
Hope this helps!