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zhannawk [14.2K]
3 years ago
10

The bakery owner will use both machines to glaze a total of doughnuts. She plans to start both machines at the same time. Based

on the rates from Parts A and B, what is the total number of hours it will take both machines working together to glaze 375 dozen doughnuts? Show or explain how you got your answer. Enter your answer and your work or explanation in the space provided.
Mathematics
1 answer:
creativ13 [48]3 years ago
5 0

Answer:

Step-by-step explanation:

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A ​$310 suit is marked down by 20​%. Find the sale price.
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the answer is 62!

Step-by-step explanation:

multiply

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if 1 gallon is equivelent to 16 cups and addibg 1 cup of vinegar makes solution. what is the ratio fraction
dolphi86 [110]

Answer:1 and 1/16

Step-by-step explanation:

7 0
3 years ago
Solve using the square root property.X^2=-12
Alla [95]

Answer:

x = ± 2i\sqrt{3}

Step-by-step explanation:

note that \sqrt{-1} = i

x² = - 12 ( take square root of both sides )

x = ± \sqrt{-12} = ± \sqrt{4(3)(-1)} = ± 2i\sqrt{3}

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2 years ago
Ask your teacher find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using i
liberstina [14]

Answer:

  ln(5/3)

Step-by-step explanation:

The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.

<h3>Limit</h3>

We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.

  \diplaystyle \lim\limits_{x\to1}{(\ln(x^5-1)-\ln(x^3-1))}=\lim\limits_{x\to1}\ln{\left(\dfrac{x^5-1}{x^3-1}\right)}\\\\=\lim\limits_{x\to1}\ln\left(\dfrac{x^4+x^3+x^2+x+1}{x^2+x+1}\right)=\ln{\dfrac{5}{3}}

8 0
1 year ago
Varies inversely as If x = 6 then y = 8. Find y when x = 4 .<br> Y=
icang [17]

Answer:

Explanation:

The statement is expressed as

y

∝

1

x

inverse means

1

variable

To convert to an equation introduce k, the constant of variation.

y

=

k

×

1

x

⇒

y

=

k

x

To find k use the given condition that y = 8 when x = 4

8

=

k

4

⇒

k

=

4

×

8

=

32

⇒

equation is

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

y

=

32

x

2

2

∣

∣

∣

−−−−−−−−−−−−

x

=

16

→

y

=

32

16

⇒

y

=

2

when

x

=

16

8 0
3 years ago
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