Answer:
The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.
Step-by-step explanation:
The volume of the sphere (
), measured in cubic feet, is represented by the following formula:

Where
is the radius of the sphere, measured in feet.
The change in volume is obtained by means of definition of total difference:

The derivative of the volume as a function of radius is:

Then, the change in volume is expanded:

If
and
, the change in the volume of the sphere is approximately:


The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.
Answer:
A D E
Step-by-step explanation:
all the other number have decimals
Answer:
<h3>5 seccs</h3>
Step-by-step explanation:
Given the modeled function of the height expressed as;
h(t)=-16t^2+64t+80
The ball hits the ground when h(t) = 0 (when the height is zero)
Substitute into the function and find t;
0 =-16t^2+64t+80
divide through by -16
0 = t²-4t-5
Factorize;
t²-4t-5 = 0
t²-5t+t-5 = 0
t(t-5)+1(t-5) = 0
(t+1)(t-5) = 0
t + 1 = 0 and t-5 = 0
t = -1 and t = 5
Time can't be negative
Hence it will take the ball 5secs before it hits the ground
Answer:
(-1,2)
Step-by-step explanation:
2(3x+5)+3x=1
6x+10+3x=1
9x+10=1
9x=-9
x=-1
y=3(-1)+5
y=-3+5
y=-2
Answer:
5/4 cups of flour
Step-by-step explanation:
3/4+1/2 = 1 1/4 or 5/4