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motikmotik
2 years ago
14

Which is the solution to the inequality?2 3/5 <b-8/15​

Mathematics
1 answer:
alexandr402 [8]2 years ago
5 0

Answer:

3 2/15 <b

Step-by-step explanation:

2 3/5 <b-8/15​

Add 8/ 15 to each side

2 3/5 + 8/ 15 <b-8/15​ + 8/15

2 3/5 + 8 /15 <b

Get a common denominator

2 3/5 *3/3 + 8/15

2 9/15 + 8/15 < b

2 17/15 < b

2 + 15/15 + 2 /15 < b

3 2/15 <b

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8. There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random without replacement.
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Answer:

a. 720

b. 0.3

Step-by-step explanation:

a.

Three balls are selected at random without replacement.

First ball can be selected in 10 ways

Second ball can be selected in 9 ways

Third ball can be selected in 8 ways

Thus, there are 10×9×8 =720 different ways of selecting three balls.

b.

There are three cases that satisfy this condition

  1. first ball picked is 5, the others are not
  2. first ball is not 5, second is 5, third is not
  3. first and second ball is not five, third ball is 5

Each probabilities are:

  1. \frac{1}{10} * \frac{9}{9} *\frac{8}{8} =\frac{1}{10}
  2. \frac{9}{10} *\frac{1}{9} *\frac{8}{8} =\frac{1}{10}
  3. \frac{9}{10} *\frac{8}{9} *\frac{1}{8} =\frac{1}{10}

Thus, one of the balls selected is the number 5 is then \frac{1}{10} + \frac{1}{10} + \frac{1}{10} = \frac{3}{10}

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3 years ago
Qtr is a right triangle TQR is a right triangle QS is an altitude which statements are true
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How many balls can Michael predict to hit if he is pitched 20 balls?
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