Is this all one equation??
Answer:
40
Step-by-step explanation:
(2x+1/(2x))^5 *(2x -1/(2x))^5
= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2
= (4x^2-1/4(x)^2)^5
now
x =4x^2. ,a = 1/4(x)^2 ,n =5
we have
general term = Cr *x^r *a^(n-r)
= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)
= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)
= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)
= Cr * 4(2r-n) *x(4r-2n)
now for x^2
4r-2n = 2
4r -10=2
4r =12
r = 3
now for coeff
C(5,3) * 4^(2*3-5)
5!/(3!*(5-3)!) * 4
5*4/(2*1)*4
40
Start off by combining like terms on the LHS (the terms with x in them).
So we get

Replacing this result with what we had before on the LHS, we get

⇒Solve for x (divide both sides

)
⇒Don't forget about reciprocity rules when dividing. This is the same as multiplying both sides by

⇒

⇒

***This is a proper fraction
When you square the radius = 6×6= 36. Multiply 36×3×3.14=339.12. Using the formula, you then multiply 1/3×339.12=339.12/3= 113.04 in^3. Final answer is 113.04^3