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Shalnov [3]
3 years ago
12

Which ordered pair is a solution to the system of linear equations Negative 4 x + y = 8 and x minus 5 y = 17? (–4, –3) (–4, 3) (

–3, –4) (–3, 4)
Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
5 0

Answer:

(–3, –4)

Step-by-step explanation:

Given pair of linear equation

-4x+y = 8    

=> y = 8 + 4x _____(1)

x - 5y = 17  (2)

substituting value of y from equation 1 in equation 2 we have

x - 5(8 + 4x) = 17

=> x - 5*8 -5*4x = 17

=> x - 40 - 20x = 17

=> -40 - 19x = 17

=> -19x = 17+40 = 57

=> x = 57/-19 = -3

Thus, x = -3

y = 8 + 4x = 8 +4(-3) = 8 -12 = -4

Thus, y = -4

Hence, paired solution for given equation is (–3, –4).

ddd [48]3 years ago
5 0

Answer:

c i got it right on the test good luck

Step-by-step explanation:

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
In right triangle ABC,
Nata [24]

Answer:

A=45°

Step-by-step explanation:

soln:

given,

ABC is a right angled triangle where C is right angle

i.e. C=90°

sin A= sin B=x(let)

A=?

we know,

A+B+C=180°[°•°sum of angles of a triangle]

or, x+x+90°=180°

or,2x=90°

•°•x=45°

hence,A=45°

6 0
3 years ago
The formula for the area of a triangle is A = ½ bh.
Triss [41]

Answer:

  1. 63 ft²
  2. h = 2A/b; h = 7 ft

Step-by-step explanation:

1. Put the values where the variables are in the formula, then do the arithmetic.

... A = (1/2)bh = (1/2)(18 ft)(7 ft) = 63 ft²

2. Divide by the coefficient of h. Substitute the given values and do the arithmetic.

... A = (1/2)bh

The coefficient of h is b/2, so we divide by that—or multiply by its inverse, 2/b.

... 2A/b = h

Substituting the given numbers, you have ...

... 2(28 ft²)/(8 ft) = h = 7 ft

The height of the triangle is 7 ft.

3 0
4 years ago
Which set contains rational numbers?
neonofarm [45]

Rational numbers are any numbers that terminate (the decimal ends somewhere)

The only set that does this is D, since

\sqrt{25}  = 5

All other sets have these:

\sqrt{47}  \:  \sqrt{7}  \: \pi

None of these terminate (the decimals goes on forever), so the answer is D

4 0
3 years ago
A house costs 36% more today than when it built.if the cost of the house today is $333200,find its cost when it was built
Brrunno [24]

Answer:

The cost of house was $245000 when it was built.

Step-by-step explanation:

Given that:

Cost of the house today = $333200

Percent increase in today's price = 36%

Let,

x be the cost of house when it was built.

100 be the percentage when the house was built.

Percentage of house price today = (100+36)% = 136%

136% of x = 333200

\frac{136}{100}*x=333200\\1.36x=333200

Dividing both sides by 1.36

\frac{1.36x}{1.36}=\frac{333200}{1.36}\\x=245000

Hence,

The cost of house was $245000 when it was built.

3 0
3 years ago
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