Answer:
Minimum unit cost = 5,858
Step-by-step explanation:
Given the function : C(x)=x^2−520x+73458
To find the minimum unit cost :
Take the derivative of C(x) with respect to x
dC/dx = 2x - 520
Set = 0
2x - 520
2x = 520
x = 260
To minimize unit cost, 260 engines must be produced
Hence, minimum unit cost will be :
C(x)=x^2−520x+73458
Put x = 260
C(260) = 260^2−520(260) + 73458
= 5,858
Answer:
-6;14
Step-by-step explanation:
x+6=0
x-14=0
I am assuming there are more than one juice box in a package so if the amount of juice boxes in each package is X and there are four packages 4X.
So 4X - 2= Answer
If we make it so that there are 6 juice boxes in each package and use the same method this is what we'll get:
24 - 2= 22
22 would be the juice boxes left over.
I hope this answers your question, if it doesn't use the same method with the number of juice boxes in a package.
Answer:180
Step-by-step explanation:
you start by finding the prime factorization of the number
5=1*5
9=3*3
12=2*2*3
the shortest way to find the factors is to find is most of them like example, at max, there are 2 two's, 2 three's and 1 five then you multiply them all together
4*9*5=180 and that's the answer
we are given
part-A:
Since, x is number of tablets
C(x) is cost of producing x tablets
so, vertical box is C(x)
so, we write in vertical box is "cost of producing x tablets"
Horizontal box is x
so, we write in horizontal box is "number of tablets"
part-B:
we have to find average on [a,b]
we can use formula
we are given point as
a: (15 , 395)
a=15 and C(15)=395
b: (20, 480)
b=20 , C(20)=480
now, we can plug values
...........Answer
part-c:
we have to find average on [b,c]
we can use formula
we are given point as
b: (20, 480)
b=20 , C(20)=480
c:(25,575)
c=25 , C(c)=575
now, we can plug values
..............Answer
