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3 years ago

What value of s makes the following equation true? s3 = −343

Mathematics

2 answers:

Simora [160]3 years ago

6 0

Answer:

s3 = -343

s = -343/3 (Decimal: s = -114.3333333)

vovikov84 [41]3 years ago

3 0

-144.33333 or -14 1/3

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The owner of a convenience store keeps track of how many customer buy lunch food during the "noon rush" each day for four days a

alexdok [17]

Answer:

c) 62.

Step-by-step explanation:

Let x represent number of customers came in on the fifth day.

We have been given that the mean number of customers for those four days is 52. So total number of customers on 4 days would be 4 times 52 that is 208 customers.

We know that mean of a data set is equal to sum of all data points divided by number of data points.

Total number of customers on 5 days would be $208+x$ and total number of days is 5.

Since we need a mean of 54, so we can set mean of 5 days equal to 54 as:

$\frac{208+x}{5}=54$

Multiply both sides by 5:

$\frac{208+x}{5}*5=54*5$

$208+x=270$

$208-208+x=270-208$

$x=62$

Therefore, 62 customers must come in on the fifth day to make the five-day mean 54 and option 'c' is the correct choice.

4 0

3 years ago

Determine whether y varies directly with x. If so, find the constant of variation k and write the equation

nydimaria [60]

y/x = k

6.4/4 = 1.6

11.2 / 7 =1.6

16/10 = 1.6

20.8 /13 =1.6

This is a direct variation and the constant is 1.6

y=1.6x

8 0

3 years ago

Read 2 more answers

A case of soda has 24 cans in it. There are 12 cases of soda. 1) What is the total number of cans of soda there are? 2) The soda

ElenaW [278]

Answer:

1) 288 cans

2) about 41 cans per team

Step-by-step explanation:

For number one you would multiply the numbers

24x12=288

there are 288 cans in total

2) divide 288 by 7 to distribute the cans evenly

each team gets about 41 cans

6 0

4 years ago

In rectangular form, 6(cos120°, isin120°)

anastassius [24]

Answer:

(-3, 3√3)

Step-by-step explanation:

Evaluate each of the coordinates. Keep or drop the "i" as your convention requires.

6(cos(120°), i·sin(120°)) = (6·cos(120°), i·6·sin(120°)) = (6(-0.5), i·6·√3/2)

= (-3, 3√3 i)

You may want the (x, y) coordinates written as (-3, 3√3).

___

In the complex plane, this is -3+i·3√3.

7 0

3 years ago

Helppop!!A car and van are driving on a highway. The table shows the amount y (in gallons) of gas in the cars gas tank after dri

Korvikt [17]

Answer:

The car uses less gas

They use the same amount of gas after $\frac{640}{7}$ miles

Step-by-step explanation:

Given

The table represents the car mileage

$y = -\frac{1}{5}x + 31$ --- The van

First, calculate the car's slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

From the table, we have:

$(x_1,y_1) = (60,13.5);\ \ (x_2,y_2) = (180,10.5)$

So, we have:

$m = \frac{10.5 - 13.5}{180 - 60}$

$m = \frac{-3}{120}$

$m = -\frac{1}{40}$

Calculate the equation using:

$y = -\frac{1}{40}(x - 60)+13.5$

$y = -\frac{1}{40}x + 1.5+13.5$

$y = -\frac{1}{40}x + 15$

$m = -\frac{1}{40}$ implies that for every mile traveled, the car uses 1/40 gallon of gas

Also:

$y = -\frac{1}{5}x + 31$ --- The van

By comparison to: $y = mx + b$

$m = -\frac{1}{5}$

This implies that for every mile traveled, the van uses 1/5 gallon of gas.

By comparison:

$1/40 < 1/5$

This means that the car uses less gas

Solving (b): Distance traveled for them to use the same amount of gas.

We have:

$y = -\frac{1}{5}x + 31$ --- The van

$y = -\frac{1}{40}x + 15$ --- The car

Equate both

$-\frac{1}{5}x + 31 =-\frac{1}{40}x + 15$

Collect like terms

$\frac{1}{40}x -\frac{1}{5}x =-31 + 15$

$\frac{1}{40}x -\frac{1}{5}x =-16$

Take LCM

$\frac{x - 8x}{40} = -16$

$\frac{- 7x}{40} = -16$

Solve for -7x

$-7x = -640$

Solve for x

$x = \frac{640}{7}$

5 0

3 years ago