Yes. 1.403 is 0.003 more than 1.4 .
So let f(x) = x^(2/3)
<span>Then let f'(x) = 2/3 x^(-1/3) = 2 / (3x^(1/3)) </span>
<span>When x = 8, </span>
<span>f(8) = 8^(2/3) = 4 </span>
<span>f'(8) = 2 / (3*8^(1/3)) = 1/3 </span>
<span>So near x = 8, the linear approximation is </span>
<span>f(x) ≈ f(8) + f'(8) (x - 8) </span>
<span>f(x) ≈ 4 + 1/3 (x - 8) </span>
<span>So the linear approximation for x = 8.03 is... </span>
<span>f(8.03) ≈ 4 + 1/3 (8.03 - 8) </span>
<span>f(8.03) ≈ 4 + 1/3 (0.03) </span>
<span>f(8.03) ≈ 4.01 </span>
<span>8.03^(2/3) ≈ 4.01 </span>
-4<em>n</em> ≥ 12 ==> <em>n</em> ≤ -3
<em>n</em> + 5 > 2 ==> <em>n</em> > -3
But <em>n</em> cannot be both less than/equal to -3 AND greater than -3, so there are no integers <em>n</em> that satisfy these inequalities.
Answer:
33
Step-by-step explanation:
snack drink entree = 3x11 because there is 11 options
