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3 years ago

solve each linear-quadratic system graphically. if necessary, round to the nearest integer. please show work

Mathematics

1 answer:

GenaCL600 [577]3 years ago

7 0

Answer:

thx sa points

Step-by-step explanation:

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2 years ago

128.09 to the nearest tenth

vaieri [72.5K]

Answer:

128.1

Step-by-step explanation:

Since this is rounding to the nearest tenth , we look at the first number after the decimal place it's 0 so we look at the second number after the decimal place which is 9 , this rounds 0 up to 1

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3 years ago

David has 4 cages of hamsters. The second cage has 1/2 as many hamsters as the first. The third cage has 1/2 as many hamsters as

atroni [7]

Answer:

1/4 of the first cage

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3 years ago

Read 2 more answers

Pls help this is very easy

anastassius [24]

Answer:

20/9

Step-by-step explanation:

Alright, so by using the "keep me, change me, turn me over" method - we can easily solve this:

$\frac{8}{9}\div \frac{2}{5}\\=\frac{8}{9}\times \frac{5}{2}\\=\frac{4}{9}\times \frac{5}{1}\\=\frac{4\times \:5}{9\times \:1}\\=\frac{20}{9}$

<em>I hope I was of assistance!</em> <em><u>#SpreadTheLove <3</u></em>

4 0

3 years ago

Help.........................<br><br>

garri49 [273]

<h3>Answer: Choice A</h3>

$x^2\left(\sqrt[4]{x^2}\right)$

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

$\sqrt[4]{x} = x^{1/4}$

The same applies to x^10 as well

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}$

Multiply the exponents 10 and 1/4 to get 10/4

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}$

$\sqrt[4]{x^{10}} = x^{10/4}$

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

$x^{m/n} = x^a\sqrt[n]{x^b}$

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

$x^{m/n} = x^a\sqrt[n]{x^b}$

turns into

$x^{10/4} = x^2\sqrt[4]{x^2}$

which means

$\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}$

7 0

3 years ago