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Nikitich [7]
2 years ago
7

Pls help (question below)

Mathematics
2 answers:
miskamm [114]2 years ago
7 0

Answer:

-3

Step-by-step explanation:

-72/24=-3

it is a negative because he is drilling down.

Tamiku [17]2 years ago
3 0

Answer:

-3

Step-by-step explanation:

-72/24

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4x^2-7x=15<br> Solve by factoring and please please please explain or show the work
vodomira [7]

Answer:

x=3 and x=-1.25

Step-by-step explanation:

4x^2-7x=15

subtract 15 from each side:

4x^2-7x-15=0

factor  (trying different numbers that the sum is 7 and the quotient is 15)

(2x-6 )(2x+2.5 )=0

2x-6=0 add 6 to each side

2x=6

x=3

2x+2.5=0   subtract 2.5 from each side

2x=-2.5

x=-1.25

8 0
3 years ago
Which of the following conversion ratios would you use to convert 780 mm to centimeters?
Westkost [7]
D. 1mm/10cm is the correct answer choice.
3 0
3 years ago
The two-way table shows information about the subjects studied
son4ous [18]

Answer:

  a) 62

  b) 31/45

Step-by-step explanation:

a) The table tells you there are 42 males, and 20 more females that study biology.

  42 +20 = 62 . . . are male or study biology or both

__

b) Of the total of 90 people, 62 are male or study biology (or both). The probability that any person is in that category is ...

  62/90 = 31/45 = P(male or biology)

4 0
2 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
What is the mean of this data set? 12,17,16,10,20,13,14,14,12,12,19,18
Gemiola [76]

Answer:

14.75 :) please give me brainliest :)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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