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alexira [117]
2 years ago
15

A daily lottery is conducted in which three winning numbers are selected out of 100 numbers​ (without duplicates). how many diff

erent combinations of winning numbers are​ possible?
Mathematics
1 answer:
Black_prince [1.1K]2 years ago
7 0
That is 100 choices for the first number
99 for the 2nd number
98 for the 3rd number

in total, there are 100*99*98 or 970200 possible combos of winning numbers
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Answer:

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Step-by-step explanation:

Step 1: Add the numbers.

20.25 can also be expressed as 20\frac{1}{4}, because \frac{2025}{100} = \frac{81}{4} = 20\frac{1}{4}. So if we add 20\frac{1}{4} and 11, we would get 31\frac{1}{4}

Step 2: Solve

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This means addition. Also, since our denominators are not the same value, we have to find the LCM (Least Common Denominator): What do 2 and 4 have in common that they can divide themselves by? 4. We know this because 2 divided by 4 is 2, and 4 divided by 4 is 1, so they can both divide themselves by 4.

\frac{5}{4}-\frac{1}{2}

LCM

\frac{5}{4}-\frac{2}{4} =\frac{3}{4}

Therefore, the simplified expression to this is 21\frac{3}{4}.

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