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tresset_1 [31]
4 years ago
13

BRAINLIEST WILL BE MARKED

Mathematics
1 answer:
zubka84 [21]4 years ago
8 0

Answer:

B. input

Step-by-step explanation:

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Solve please. Correctly<br> 3(1 - 2a) = -3a - 18
True [87]

Answer:

a = 7

Step-by-step explanation:

3(1 - 2a) = -3a - 18

3 - 6a = - 3a - 18

Add 18 to each side:

3 + 18 - 6a = - 3a - 18 + 18

21 - 6a = - 3a

Add 6a to each side:

21 - 6a + 6a = - 3a + 6a

21 = 3a

3a = 21

Divide each side by 3:

3a ÷ 3 = 21 ÷ 3

a = 7

6 0
3 years ago
Hi my question is what is 72x13​
wariber [46]
936 is the answer :)))))))))))
4 0
3 years ago
Read 2 more answers
Can someone help me with these both
Anna [14]
Hello,
so all you have to do is match the abbreviations to the triangles. The abbreviations stand for what is the SAME in both triangles, denoted by similar markings on equal sides and angles.

Abbreviations:
SSS = Side-Side-Side
SAS = Side-Angle-Side
ASA = Angle-Side-Angle
AAS = Angle-Angle-Side
HL = Hypotenuse-Leg

* Note - the angle side angle must go around the triangle in that order. ASA has the side BETWEEN the congruent angles.. SSA does NOT work.

(9.) ASA
(10.) AAS
(11.) SSS
(12.) No way to tell if congruent. (only 3 angles no side)
(13.) ASA
(14.) SAS
(15.) HL

7 0
3 years ago
Calculate the sum of 12.7, 24.8, 4.1
adell [148]
41.6 is the answer I got
4 0
4 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
Read 2 more answers
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