Answer:
Percent error = 4.29%
Step-by-step explanation:
Percent error can be defined as a measure of the extent to which an experimental value differs from the theoretical value.
Mathematically, it is given by this expression;
Given the following data;
Experimental value = 67
Theoretical value = 70
Substituting into the equation, we have;
Percent error = 4.29%
Answer:
2
Step-by-step explanation:
7x + 3 = 8x + 1
2 = x
these are geometry problems.
Let the width be W, then the length is 4W (since the width is 1/4 the length)
The area of the original deck is

The dimensions of the new deck are :
length = 4W+6
width=W+2
so the area of the new deck is :

"<span>the area of the new rectangular deck is 68 ft2 larger than the area of the original deck</span>" means that we write the equation:




the length is

ft
Answer: width: 4, length: 16
2.1+18.9
The answer is going to be 21 because 9+1=10, you then carry the 1 for 8 so it’s going to be 9+2 which equals to 11 now you carry the 1 to the 1 so it’ll be 2. Therefore it’s 21.0 or just cancel out the 0 and just leave it as 21.
Answer:
<em>AB = 7.35 cm</em>
Step-by-step explanation:
From the attachment,
In ΔDEF,
DF = GH-(GD+FH) = 6 - (2+3) = 1 cm
DE = 2+3 = 5 cm (sum of two radius)
Applying Pythagoras theorem,

In ΔCDI,
DI = GH-(GD+IH) = 6 - (2+1.5) = 2.5 cm
CD = 2+1.5 = 3.5 cm (sum of two radius)
Applying Pythagoras theorem,

AB = EF + CI = 