We want
to divide
, i.e.
.
So, assume that we have a number
such that
![\dfrac{3p-k}{p-1}=\alpha](https://tex.z-dn.net/?f=%5Cdfrac%7B3p-k%7D%7Bp-1%7D%3D%5Calpha)
This implies that
![3p-k=\alpha(p-1)=\alpha p-\alpha](https://tex.z-dn.net/?f=3p-k%3D%5Calpha%28p-1%29%3D%5Calpha%20p-%5Calpha)
Those two expression are equal if the correspondent coefficients are equal:
![3p-k=\alpha p-\alpha \iff \begin{cases}3=\alpha\\-k=-\alpha\end{cases}\iff \begin{cases}3=\alpha\\k=\alpha\end{cases}](https://tex.z-dn.net/?f=3p-k%3D%5Calpha%20p-%5Calpha%20%5Ciff%20%5Cbegin%7Bcases%7D3%3D%5Calpha%5C%5C-k%3D-%5Calpha%5Cend%7Bcases%7D%5Ciff%20%5Cbegin%7Bcases%7D3%3D%5Calpha%5C%5Ck%3D%5Calpha%5Cend%7Bcases%7D)
And it should be immediate to conclude the value for k from here.
what is the question that you are asking you are only giving information
5.00+0.67+0.07 that's it I believe
Answer:
(-3, 2)
Step-by-step explanation:
T -5,3 is a transformation down 5 and right 3 so you would add/subtract it from (2, -1)
So you do 2 -5 = -3
And -1 +3 = 2