Question

Of three positive integers, the second is twice the first, and the third is twice the second. One of these integers is 17 more than another. What is the sum of the three integers?

Answer 1

X = 1st integer, y = 2nd integer, z = 3rd integer

y = 2x
z = 2y......z = 2(2x)...z = 4x

y = x + 17
2x = x + 17
2x - x = 17
x = 17

y = 2x
y = 2(17)
y = 34

z = 4x
z = 4(17)
z = 68

and the sum would be : 17 + 34 + 68 = 119