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3 years ago

Find the volume please helpppp

Mathematics

1 answer:

pentagon [3]3 years ago

4 0

The formula to solve a cylinder is V=πr²h

So, round pi to 3.14

We must plug in for the radius (r) in this equation. To do this, we must half up the diameter, 5. 5/2 = 2.5

6 is height

V=3.14 * 2.5² * 6

V=117.81 we must round though to tenth, and that would be:

Answer V=117.8m³

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What combination of transformations is shown below?

Anastasy [175]

Answer:

Rotation then reflection

Step-by-step explanation:

The triangle starts where the light green one is. Then it is rotated 90 degrees clockwise around the point where the hypotenuse and longer leg meet. From the sark green triangle it is reflectd to where the purple triangle is.

8 0

3 years ago

BRAINLIST ASAP

kifflom [539]

Answer:

25.50

Step-by-step explanation:

-5 notebooks $2 each

-4 pencils $1.50 each

-2 packs of markers $3.75 each

5(2)+4(1.50)+2(3.75)

$23.5

23.5 times 8.5/100

1.9975

plus 23.5

25.4975

rounded to 25.50

6 0

3 years ago

The area of a rectangle that has a length of 10 and a width of w.

alexdok [17]

Answer:

Step-by-step explanation:

To find the area, multiply length by width (lw, or l×w). If the length is 10, that just leaves the width, which is unknown. We can substitute 10 for l, which leaves us with 10w.

8 0

3 years ago

Hyxetdryufgukhchfxrdtygujhftyuhuhyguhjygyu

nikklg [1K]

Answer:

so the answer is: eijieljnqwsmiqwmx

did i answer it correctly let me know

Step-by-step explanation:

Destroy your keyboard by smashing each random word on the poor broken keyboard

6 0

3 years ago

Read 2 more answers

The meat department of a local supermarket packages ground beef using meat trays of two sizes: 1 designed to hold 1 lb of meet a

r-ruslan [8.4K]

Answer:

c) 0.932

99% confidence interval for average weights of all packages sold in small meat trays.

(0.932 ,1.071)

Step-by-step explanation:

Explanation:-

Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation of 0.18 lbs.

size of the sample 'n' = 35

mean of the sample x⁻= 1.01lbs

standard deviation of the sample 'S' = 0.18lbs

The 99% confidence intervals are given by

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} +t_{\alpha } \frac{S}{\sqrt{n} } )$

The degrees of freedom γ=n-1 =35-1=34

tₐ = 2.0322

99% confidence interval for average weights of all packages sold in small meat trays

$(1.01 - 2.0322 \frac{0.18}{\sqrt{35} } , 1.01+2.0322 \frac{0.18}{\sqrt{35} } )$

( 1.01 - 0.06183 , 1.01+0.06183)

(0.932 ,1.071)

Final answer:-

99% confidence interval for average weights of all packages sold in small meat trays.

(0.932 ,1.071)

5 0

3 years ago