Which expression can be used to find the surface area of the following square pyramid

Mathematics

2 answers:

STatiana [176]3 years ago

7 0

The answer is a 36 + 15 + 15+ 15 +15

mariarad [96]3 years ago

5 0

Answer:

a. 36+15+15+15+15

Step-by-step explanation:

The base of the pyramid is a square. We know that all sides of a square are equal so if we multiply the two sides of the base square(6*6) we get 36.

The area of a triangle can be found with the formula (b*h)/2. If we input the given values of 5 and 6 into our equation, then (5*6)/2 is 15 and since there are 4 triangles in the square pyramid, you multiply 15 by 4 (or add 15+15+15+15), and add the 36 from the base square.

Hope this helps :)

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What is the value of the expression if m = –5 and n = 3? Negative StartFraction 24 Over 25 EndFraction Negative StartFraction 4

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You can use the fact that a number raised to negative powers can be written as 1 divided by that number raised to positive number.

The value of the given expression when m = -5 and n= 3 is $-\dfrac{2}{5}$

<h3>How can we rewrite a number raised to negative power?</h3>

Suppose we've got $a^{-b}$ . then it can be rewritten as

$a^{-b} = \dfrac{1}{a^b}$

It is because $a^0 = 1$ for any a except 0, and that $\dfrac{a^0}{a^b} = a^{0-b} = a^{-b}$

If base are same and there is multiplication, then there will be addition in power.

Also, know the fact that if base are same and there is division, there will be subtraction in power(subtracting since that denominator when goes up, its power gets negated(gets negative sign to the existing power)

Thus,

$a^b \timesa ^c = a^{b+c}\\\\\dfrac{a^b}{a^c} = a^{b-c}$

<h3>Using above method to simplify the given expression before evaluating</h3>

The given expression is $\dfrac{2m^{-1}n^5}{3m^0n^4} = \dfrac{2n^5}{3m^0m^1n^4} = \dfrac{2n^5}{3mn^4} = \dfrac{2n^{5-4}}{3m} = \dfrac{2n^1}{3m} = \dfrac{2n}{3m}$