Answer:
Step-by-step explanation:
KL = JK, so ΔJKL is an isocesles triangle, then m∠J = m∠L
KL is a tangent line, so ∠JKL = 90°,
so m∠J = 45°
When (2x-20)＋86＝0
2x-20＝-86
2x＝-46
x＝-23
Answer:
57.78 km/hr
Step-by-step explanation:
Total time taken, t = 6 hours
Total distance covered, d = 520 km
Distance by car = 260
Distance by train = 520 - 260 = 260 km
Train speed = x
Car speed = 2x
Average speed speed = 3x /2
Speed = distance / time
1.5x = 520 / 6
9x = 520
x = 520 / 9
x = 57.777
Average speed of train = 57.78 km/hr
For this case we must find the value of the variable "x" of the following equation:
We multiply by 3 on both sides of the equation:
We divide between 2 on both sides of the equation:
We subtract 7 on both sides of the equation:
Answer:
Option B
