A 79-tooth gear drives a smaller gear which has 42 teeth. If the larger gear rotates at 316 rpm, what is the speed of the smalle
r gear, to the nearest rpm?
1 answer:
Answer:
594 rpm
Step-by-step explanation:
Two gears will have the same linear speed, so:
v₁ = v₂
ω₁ r₁ = ω₂ r₂
(316 rpm) (79) = ω (42)
ω ≈ 594 rpm
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<em>I hope this helps! :)</em>
