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den301095 [7]
4 years ago
9

Can someone solve and explain how to do this for me

Mathematics
1 answer:
Jobisdone [24]4 years ago
3 0
Ok
You look at how many ‘x’ there are then you add them together 6x+3x+x+10+40=180
I think you can take it from here?
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Nady [450]

Answer:

12.50x+30

Step-by-step explanation:

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Colinda has just purchased her first home for $125000. she put down a 20%payment of $25000 and took 4% percent mortgage for the
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Since there was a down payment, the actual amount borrowed was
Amount borrowed, P=125000-25000=100000
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Ali multiplies 3 numbers using the expressions a x (b x
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Wittaler [7]

(1) ∠ABC = 65°, ∠DBE = 65°, ∠CBE = 115°, ∠ABD = 115°

(2) ∠ABC = 62°, ∠DBE = 62°, ∠CBE = 118°, ∠ABD = 118°

Solution:

(1) In the given image ABC and DBE are vertical angles.

<u>Vertical angle theorem:</u>

If two angles are vertical then they are congruent.

⇒ ∠ABC = ∠DBE

⇒ 3x° + 38° = 5x° + 20°

Arrange like terms one side.

⇒ 38° – 20° = 5x° – 3x°

⇒ 18° = 2x°

⇒ x° = 9°

∠ABC = 3(9°) + 38° = 65°

∠DBE = 5(9°) + 20° = 65°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 65° + ∠CBE = 180°

⇒ ∠CBE = 115°

∠ABD and ∠CBE are vertical angles.

∠ABD = 115°

(2) In the given image ABC and DBE are vertical angles.

⇒ ∠ABC = ∠DBE

⇒ 4x° + 2° = 5x° – 13°

Arrange like terms one side.

⇒ 13° + 2° = 5x° – 4x°

⇒ 15° = x°

∠ABC = (4(15°) + 2°) = 62°

∠DBE = 5(15°) – 13° = 62°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 62° + ∠CBE = 180°

⇒ ∠CBE = 118°

∠ABD and ∠CBE are vertical angles.

∠ABD = 118°

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I mark brainliest.......
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Answer:

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Step-by-step explanation:

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