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iris [78.8K]
3 years ago
13

What is the slope between the points (4,5) and (-3,6)

Mathematics
2 answers:
erica [24]3 years ago
6 0
You would use the slope equation, (y1-y2)/(x1-x2)
 
plug in the y coordinates and the x coordinates and you'll get:

-1/7
Tatiana [17]3 years ago
6 0
Using the equation (Y2-Y1)/(X2-X1) you can find the slope is 

m= 1/-7 
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A fraction in which the GCF of the numerator and the denominator is 1 is written in
konstantin123 [22]
"lowest terms". Whenever 2 numbers have a GCF of 1, that means there isn't anything that can divide out of both numbers, which is called "lowest terms." It means that the fraction cannot be reduced any more.
5 0
3 years ago
PLEASE HELP I DONT UNDERSTAND I HAVE A FEW MIN TO SUBMIT
Lunna [17]

Answer:

Increasing: (\infty, -1) \cup (2, \infty)

Decreasing: (-1, 2)

Step-by-step explanation:

So when an equation has and odd degree, it will go in the opposite direction on both ends, so if y went towards infinity as x went towards infinity, then y would go towards negative infinity as x goes towards negative infinity. In this case, by looking at the graph it has an odd degree, due to opposite end behaviors, although on both ends it's increasing because even though it appears that it's going down on the left side, that's only if you start from the right and go towards the left. So it's really increasing from negative infinity to -1, and then it decreases from -1 to 2, until it once again starts increasing from 2 to infinity. This can be represented as (-infinity, -1) U (2, infinity) for increasing and (-1, 2) as decreasing

4 0
1 year ago
Sierra is saving for a bike and helmet.
Goshia [24]
It would be 806 of 16
8 0
2 years ago
Tana-tanb/cotb-cota=tana*tanb
Tems11 [23]

Answer:

cot is an inverse function or rival of tan:

{ \boxed{ \bf{ \cot( \theta) =  \frac{1}{ \tan( \theta) }  }}}

Considering the question:

{ \tt{ \frac{ \tan( a) -  \tan(b)  }{ \cot(b) -  \cot(a)  }  =  \tan(a) . \tan(b) }} \\ \\  { \tt{ \tan(a)  -  \tan(b)  = ( \tan(a). \tan(b) )( \cot(b) -   \cot(a)  ) }} \\ { \tt{ \tan(a) -  \tan(b)  =  \tan(a)  \cot(b)  \tan(b)   -  \cot(a)  \tan(a) \tan(b)  }} \\ \\  { \tt{ \tan(a) -  \tan(b) =  \frac{ \tan(a) \tan(b)  }{ \tan(b) }   -  \frac{ \tan(a) \tan(b)  }{ \tan(a) }  }} \\  \\ { \tt{ \tan(a)  -  \tan(b) =  \tan(a)  -  \tan(b)  }}

#Hence L.H.S = R.H.S, equation is consistent.

6 0
2 years ago
What is the point-slope form of a line with slope 3 that contains the point<br> (2, 1)?
Setler [38]

Answer:

y-1 = 3(x-2)

Step-by-step explanation:

The point slope form of a line is

y-y1 = m(x-x1)

where m is the slope and (x1,y1) is a point on the line

y-1 = 3(x-2)

3 0
2 years ago
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